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-Dominant- [34]
3 years ago
5

What is 0.03 in scientific notation

Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer: 3e-1

Step-by-step explanation: when it's going behind the decimal it will always be negative plus the reason it's one is because if you slide the decimal once it'll be the complete opposite

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DMAS
777dan777 [17]

Answer: 55

Step-by-step explanation:

Let the number of cars washed last year be denoted as x.

This year, he washed 14 fewer cars than during last year's car wash. This will be denoted as x-14.

We can then represent them in an equation as:

x + (x - 14) = 96

2x - 14 = 96

2x = 96 + 14

2x = 110

x = 110/2

x = 55

Therefore, he washed 55 cars this year

7 0
3 years ago
How to find variables of these #2 & #3
Lubov Fominskaja [6]
So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles  like  \bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}

now.. for 3) will be the second picture below


\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}

8 0
3 years ago
What are the next three terms in the sequence 11,18,25,32
Marat540 [252]
39 it's an arithmetic sequence in which the common difference is +7
8 0
3 years ago
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If x = 2y + 2, how much greater is 6x than 12y?
ziro4ka [17]
I think that it is A
4 0
3 years ago
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Evaluate the expression 8x - 10 when x = 4
serg [7]
Answer: 8(4) - 10 equals to 22 :)
4 0
3 years ago
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