42/98=3/7
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Since the rate of descent is a constant this is a linear equation and can be expressed as:
h=vt+b, where h=feet, v=slope or rate, b=y-intercept (y value when x=0 which is the initial height)
h=-2t+b, using the point (3,67) we can solve for b, or the initial height
67=-2(3)+b
67=-6+b
73=b so the initial height was 73 ft and the height equation is then:
h(t)=67-2t so when t=8 you have:
h(8)=67-2(8)
h(8)=67-16
h(8)=51 ft
Answer:
Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4
Step-by-step explanation:
I attached the graph of the function.
Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0
When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2)) 
3x4=12 12x5=60 60x6=360 360x7=2,530 2,530x9=22,690
Answer:
I am not getting what is this