Answer:
years 1–4: 62.4 bass per year
years 5–8: 67.6 bass per year
Step-by-step explanation:
If the population in year n is ...
p(n) = 3000·1.02^n
then the average rate of change from year 1 to year 4 is ...
(p(4) -p(1))/(4 -1) = 3000(1.02^4 -1.02^1)/3 = 1020·(1.02^3 -1) ≈ 62.4
The average rate of change for years 1–4 is 62.4 bass per year.
For years 5–8, the rate of change is similarly computed:
(p(8) -p(5))/(8 -5) = 3000(1.02^8 -1.02^5)/3 = 1000·1.02^5·(1.02^3 -1) ≈ 67.6
The average rate of change for years 5–8 is 67.6 bass per year.
Answer: A
Step-by-step explanation: you go 10 to the 8th^, and 10 to the 6th^
Answer:
2a +7
Step-by-step explanation:
