The ordered pair of the point I' is (-0.8, 2.4)
<h3>The complete question</h3>
Hexagon IJKLMN is shown on the coordinate plane below. If hexagon IJKLMN is dilated by a scale factor of two fifths from the origin to create hexagon I'J'K'L'M'N', what is the ordered pair of point I'?
<h3>How to evaluate the ordered pair of point I'?</h3>
From the complete question, the ordered pair of point I is given as:
I = (-2,6)
The scale factor (k) is given as:
k = 2/5
The image of the dilation is calculated using:
I' = I * k
This gives
I' = (-2,6) * 2/5
Evaluate
I' = (-0.8, 2.4)
Hence, the ordered pair of point I' is (-0.8, 2.4)
Read more about dilation at:
brainly.com/question/3457976
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Answer:
-5/6
Step-by-step explanation:
(25/4)^(3x) = 32/3125
Rewrite as powers of 2 and 5:
(5²/2²)^(3x) = 2⁵/5⁵
Rewrite the left side as the inverse:
(2²/5²)^(-3x) = 2⁵/5⁵
Solve for the exponent:
-3x = 5/2
Solve for x:
x = -5/6
Answer:
3x-2
Step-by-step explanation:
2x+x2-x2= 3x-2
The correct answer is: [A]: " 29.4 ft. "
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Explanation:
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Solve for "b" ; which is the "base" .
14.7 ft. = (1/2) * b ;
→ (1/2) * b = 14.7 ft ;
Multiply EACH SIDE of the equation by "2" ;
to isolate "b" on one side of the equation; & to solve for "b" ;
___________________________________________________2 * { (1/2) b } = 2 * (14.7 ft) ;
to get:
b = 29.4 ft . ;
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→ which is: Answer choice: [A]: " 29.4 ft. "
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Answer:
a = 14
Step-by-step explanation:
Given
9 + a = 23 ( subtract 9 from both sides )
a = 14
