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3 years ago

4x/x^2+1 what the graph for the equation

Mathematics

1 answer:

navik [9.2K]3 years ago

4 0

Answer:

Step-by-step explanation:

I recommend using desmos when wnating to see how a graph looks! hope this helped

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Solve by using proper methods. Show your work.

NeX [460]

Answer:

$70,201.38

Step-by-step explanation:

To determine the principal amount, we can use the formula:

$P=\dfrac{A}{(1+\frac{r}{n})^{nt}}$

A = $200,000

r = 7% or 0.07

t = 15 years

n = 12

Now let's substitute our values.

$P=\dfrac{200,000}{(1+\frac{0.07}{12})^{12(15)}}$

$P=\dfrac{200,000}{(1.00583333333)^{12(15)}}$

$P=70,201.38$

So the principal needed to get 200,000 in 15 years is $70,201.38.

7 0

3 years ago

Round .086 to leftmost nonzero digit

alekssr [168]

If it's a whole number it would be 1 and of it wasn't it's .1 or .09

6 0

3 years ago

PLEASE HELP I GIVE THANKS

Sever21 [200]

D
because first you times z and x to get the area and then you multiply that by two added to
h times y divided by two (area of a triangle) times again by two cuz theres two sides
finally add z times y cuz thats the area of the base
and you get 896

8 0

3 years ago

Read 2 more answers

Determine whether the relation is a function.<br><br> (-3,3), (-2,2), (-1,1), (1,-1), (2,-2), (3,-3)

Luba_88 [7]

Answer:

Function

Step-by-step explanation:

Because there is an output for every input listed of its opposite.

3 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago