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3 years ago

If y varies directly with x, and y is 14 when x is 2, what is the value of x when y is 35?

Mathematics

2 answers:

Leno4ka [110]3 years ago

6 0

The answer to this question is 5

Ainat [17]3 years ago

4 0

Im pretty sure it's 17.5 since 35 is odd.

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Please help, this makes no sense to me

aev [14]

Answer:

7/11

Step-by-step explanation:

Let X equal the decimal number

Equation 1:

X=0.63¯¯¯¯¯

With 2 digits in the repeating decimal group,

create a second equation by multiplying

both sides by 102 = 100

Equation 2:

100X=63.63¯¯¯¯¯

Subtract equation (1) from equation (2)

100XX99X===63.63...0.63...63

We get

99X=63

Solve for X

X=6399

Find the Greatest Common Factor (GCF) of 63 and 99, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 9,

63÷999÷9=711

Therefore

X=711

In conclusion,

0.63¯¯¯¯¯=711

used

https://www.calculatorsoup.com/calculators/math/decimal-to-fraction-calculator.php

6 0

3 years ago

Welppp fastttt!!!!!!!!!!!!!!!!!!

Romashka [77]

Answer: B

Step-by-step explanation:

Grade must be greater than or equal to 88

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3 years ago

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2. Give an example of how you use positive and negative numbers in the real world. Be sure to explain the meaning of 0 in your e

geniusboy [140]

Temperature under 0 Degrees it snows. Also my brain is always right

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3 years ago

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Whats the highest number you have ever counted to?

Vlada [557]

Answer:

i think it was 1,260 something

Step-by-step explanation:

i was counting the seconds it would take for my sister to put her bike back in the garage, lol :)

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3 years ago

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by

11111nata11111 [884]

Answer:

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is $V=l\times b\times h$

$V=(11-2x)\times (7-2x)\times x$

$V=4x^3-36x^2+77x$

Derivate w.r.t x,

$V'(x)=4(3x^2)-2(36x)+77$

$V'(x)=12x^2-72x+77$

The critical point when V'(x)=0

$12x^2-72x+77=0$

Solve by quadratic formula,

$x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}$

$x=4.607,1.392$

Derivate again w.r.t x,

$V''(x)=24x-72$

Now, $V''(4.607)=24(4.607)-72=38.568>0$ (+ve)

$V''(1.392)=24(1.392)-72=-38.592$ (-ve)

So, there is maximum at x=1.392.

The length of the box is $l=11-2x$

$l=11-2(1.392)=8.216$

The breadth of the box is $b=7-2x$

$b=7-2(1.392)=4.216$

The height of the box is h=1.392.

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is $V=l\times b\times h$

$V=8.216\times 4.216\times 1.392$

$V=48.217\ in.^3$

The volume of the box is 8.217 cubic inches.

5 0

3 years ago