Solve the absolute value equation 4 − |x| = 1

Mathematics

2 answers:

antiseptic1488 [7]3 years ago

8 0

Answer:

x can equal 5 or -5 since absolute value changes everything into a positive number.

Step-by-step explanation:

VMariaS [17]3 years ago

5 0

Answer :SOLVING EQUATIONS CONTAINING ABSOLUTE VALUE(S)

Step 1: Isolate the absolute value expression.

Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.

Step 3: Solve for the unknown in both equations.

Step 4: Check your answer analytically or graphically.

Step-by-step explanation:

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For each problem, identify any important quantities. If it's a known quantity, write the

Tema [17]

Answer:

We have the problem:

"Clare is in charge of getting snacks for a road trip with her friends and her dog. She has

$35 to go to the store to get some supplies. The snacks for herself and her friends cost

$3.25 each, and her dog's snacks costs $9 each."

In this situation we have two variables:

X = number of snacks for herself and her friends that she buys. Each one of these costs $3.50

Y = number of snacks for her dog that she buys. Each one of these costs $9.

The total cost, in this case, can be written as:

X*$3.50 + Y*$9

And we know that she has $35 to spend, so she can spend $35 or less in the store, then we have the inequality:

X*$3.50 + Y*$9 ≤ $35

Where we defined all the quantities in the inequality.

4 0

3 years ago

The graph shows the result of a matrix transformation, where the pre-image has dashed lines Which matrix operation is represente

diamong [38]

The matrix operation is the addition subtraction and multiplication involving matrices. The coordinates of the image can be represented as a matrix obtained from the coordinates of the preimage through matrix operations

The best correct option is option D), (the y-coordinate for the point (8, -7) is to be replaced with a 7 to give (7, -7) as follows:

$\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]$

The reason the above matrix value for the matrix operation are correct are as follows:

Known parameters:

From the diagram, we have that the coordinates of the vertices of the preimage are;

(2, -5), (3, -7), (9, -3), and (7, -7)

The coordinates of the vertices of the image are;

(2, 5), (3, 7), (9, 3), and (7, 7)

Required:

The matrix operation for the transformation of the preimage points to the image points

Solution:

The transformation from the coordinates of the vertices of primage to the vertices of image involves the change in the sign from negative to positive, of the y-values of the image, which can be obtained by multiplying by (-1)

Therefore, the required matrix operation is presented as follows:

$\mathbf{\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]} =\left[\begin{array}{rrrr}9&7&3&2\\3&7&7&5\end{array}\right]$