Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation
Calculate z-scores for the following random variable and determine their probabilities from standard tables.
x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088
x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912
x = 65 in
z = (65 - 68)/3 = -1
P(x) = 0.1587
x = 71:
z = (71-68)/3 = 1
P(x) = 0.8413
Part (a)
For x > 72 in, obtain
300 - 300*0.9088 = 27.36
Answer: 27
Part (b)
For x ≤ 64 in, obtain
300*0.0912 = 27.36
Answer: 27
Part (c)
For 65 ≤ x ≤ 71, obtain
300*(0.8413 - 0.1587) = 204.78
Answer: 204
Part (d)
For x = 68 in, obtain
z = 0
P(x) = 0.5
The number of students is
300*0.5 = 150
Answer: 150
Answer:
a) d = 3.6t
b) 10.8 miles
c) 1.2 hours
Step-by-step explanation:
For part a:
Slope of a line: y = mx + b
In this case, the equation would be: d = mt,
where m represents the speed Caden is walking at.
Note: b = 0 in this case because when Caden starts walking on the treadmill, he hasn't really covered any distance yet.
Therefore, plugging in a speed of 3.6 miles per hour, the equation is:
d = 3.6t
For part b:
This is a simple instance of plugging in 3 hours for our t value.
Therefore, d = 3.6 (3)
d = 10.8 miles
For part c:
In this case, we are given that d = 4.32 miles.
Therefore, 4.32 = 3.6t
Dividing both sides by 3.6, we get
t = 1.2 hours
Answer:
Square Root of 384
Step-by-step explanation:
Plant (A) have a higher median at 6 and the IQR is low at 3, however, Plant (B) has a lower median of 5 but High IQR of 4 so the Plant (B) is growth is high.
hopes loves.
