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DENIUS [597]
3 years ago
15

A new car that costs $17,500 loses 25 percent of its value in the first year. How much is the loss of the value.

Mathematics
1 answer:
EastWind [94]3 years ago
4 0

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{25\% of 17500}}{\left( \cfrac{25}{100} \right)17500}\implies 4375

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Write 2 different equations with a sum of 9/5.
Julli [10]
Two possible equations are:

\dfrac{5}{5} +   \dfrac{4}{5}   = \dfrac{9}{5}

\dfrac{2}{5} +   \dfrac{7}{5}   = \dfrac{9}{5}
8 0
3 years ago
X2 - __________x + 144
Yakvenalex [24]

Answer:

the blank =24x

Step-by-step explanation:

Assuming the expression is x^2 - ________x +144,

you can tell that this is in the form of a^2 +2ab+b^2.

If the "a" is squared, you would get x^2. And if the "b" was squared then you would get b^2.

So as the result, the expression is

(x-12)^2= x^2-24x+144

5 0
2 years ago
Simultaneous equations:
Mazyrski [523]

Answer:

1. x = 4 and y = 1

2. x= 5 and y = 3

Use the examples below to complete 3 and 4.

Step-by-step explanation:

To solve each system of equations, use elimination.

1. Stack the equations and subtract to perform elimination.

 2x + 2y = 10

-   x + 2y = 6

-------------------------

     x         = 4

Substitute x = 4 into an equation to solve for y.

2(4) + 2y = 10

8 + 2y = 10

2y = 2

y = 1

2. Stack the equations and subtract to perform elimination.

 3x + y = 18

- 2x + y = 13

-------------------------

     x         = 5

Substitute x = 5 into an equation to solve for y.

3(5) + y = 18

15 + y = 18

y = 3

Continue the same method for numbers 3 and 4.

3 0
3 years ago
A certain system can experience three different types of defects. Let Ai (i = 1,2,3) denote the event that the system has a defe
emmainna [20.7K]

a.

P({A_1}^c)=1-P(A_1)=\boxed{0.86}

b.

P(A_1\cap A_2)=P(A_1)+P(A_2)-P(A_1\cup A_2)=\boxed{0.07}

c. By the law of total probability,

P({A_3}^c)=P((A_1\cap A_2)\cap{A_3}^c)+P((A_1\cap A_2)^c\cap{A_3}^c)

According to the inclusion/exclusion principle,

P((A_1\cap A_2)^c\cap{A_3}^c)=P((A_1\cap A_2)^c)+P({A_3}^c)-P((A_1\cap A_2)^c\cup{A_3}^c)

but by DeMorgan's law,

(A_1\cap A_2)^c\cup{A_3}^c={A_1}^c\cup{A_2}^c\cup{A_3}^c=(A_1\cap A_2\cap A_3)^c

So

P((A_1\cap A_2)^c\cap{A_3}^c)=(1-P(A_1\cap A_2))+(1-P(A_3))-(1-P(A_1\cap A_2\cap A_3))

and from there we find

P(A_1\cap A_2\cap{A_3}^c)=P((A_1\cap A_2\cap A_3)^c)-P((A_1\cap A_2)^c)=\boxed{0.05}

d. The event of having at most two of these defects is complementary to the event that all three defects occur simultaneously:

P((A_1\cap A_2\cap A_3)^c)=1-P(A_1\cap A_2\cap A_3)=\boxed{0.98}

3 0
3 years ago
What is this answer? A B C OR D?
Delicious77 [7]

Answer:

B I believe I'm a little rusty on math

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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