Answer:
5x^7y^11.
Step-by-step explanation:
∛(125x^21 y^33)
The cube root = 'to the power 1/3' so we have:
125^1/3 * x^(21*1/3) * y^(33*1/3)
5x^7y^11.
Answer:
Range of the function → {24, 375}
Step-by-step explanation:
Domain of the function f(x) = 3x³ is {2, 5}
we have to find the range when its domain is {2, 5}
Since x-values of any function define the domain and y-values define the range.
For x = 2,
f(2) = 3(2)³ = 24
For x = 5,
f(5) = 3(5)³ = 375
Therefore, range of the given function for the given domain will be {24, 375}.
I think it’s 9.10 but I’m not really sure
It would be 90%..... 45/450= 10%.... so there would be 90% not being used.
