Answer:
n = all real numbers
Step-by-step explanation:
7n+12=1/2(14n+24)
multiply each side by 2
2(7n+12)=2*1/2(14n+24)
distribute
14n+24 = 14n + 24
subtract 14n from each side
14n-14n+24 = 14n-14n + 24
24=24
this is always true
n = all real numbers
There is a 33.3% chance of rolling a number less than 6. It’s 2/6, which is reduced to 1/3. = that to x/100, multiply 1 x 100, and divide that by 3. So it’s 100 divided by 3, and that’s 33.3, which is the percentage.
Using the normal distribution, we have that:
- The distribution of X is
.
- The distribution of
is
.
- 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
- 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem, the parameters are given as follows:

Hence:
- The distribution of X is
.
- The distribution of
is
.
The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:
X = 58:


Z = 0.05.
Z = 0.05 has a p-value of 0.5199.
X = 55:


Z = -0.1.
Z = -0.1 has a p-value of 0.4602.
0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
For the sample of 17 movies, we have that:
X = 58:


Z = 0.19.
Z = 0.19 has a p-value of 0.5753.
X = 55:


Z = -0.38.
Z = -0.38 has a p-value of 0.3520.
0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.
More can be learned about the normal distribution at brainly.com/question/4079902
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Let's find the area of the base first:
7×7=49
The S stands for the sides of the base. Since you are multiplying them by each other, you are basically squaring them.
Let's now multiply the area of the base by the height.
49×12=588
Now, let's multiply by 1/3.
588×1/3 or 588÷3
196
So, the volume is 196 ft³.
There is not sufficient evidence to support the claim that over 40% of the public recognize its brand name and associate it with computer equipment thus the company should not continue to advertise during the Super Bowls. So No. Hope I helped have a good day !