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solmaris [256]
3 years ago
15

What is 209 rounded to nearest ten

Mathematics
2 answers:
vitfil [10]3 years ago
8 0
210 because 209 is closer to 210 then 200.
JulsSmile [24]3 years ago
5 0
210 because 209 is closer to 210 than to 200
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Nimfa-mama [501]
They are both in standard form.
7 0
3 years ago
if you were asked to load 225 boxes onto a truck and the boxes are crated with each crate containing nine boxes how many crates
jeyben [28]
25

Steps: 225 / 9 = 25 crates
4 0
3 years ago
IF I GET AN ANSWER IN 10 MIN UR VOTED BRAINLIEST
Over [174]

Adding and subtracting with negative numbers

First, recognize that adding and subtracting are, from one viewpoint, the same thing. Subtracting a number is the same thing as adding the negative of that number. For example, 4 – 12 is the same as 4 + –12 (which, because the order of terms doesn't matter with addition, is the same as –12 + 4). With that in mind, here are the rules for adding with negative and positive numbers:

If both numbers are positive, then the answer is positive.

If both numbers are negative, then the answer is negative.

If the numbers have different signs, the answer takes the sign of the higher number.

Subtracting a negative number is the same as adding the positive of that number. For example, 5 – –4 is the same as 5 + 4.

Multiplying and dividing with negative numbers if the numbers have different signs, the answer is negative.

3 0
3 years ago
Find all values of the angle θ (in radians, with 0 ≤ θ < 2π) for which the matrix a = cos θ −sin θ sin θ cos θ has real eigen
harina [27]

The matrix

A=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix}

has eigenvalues \lambda such that

\det(A-\lambda I)=\begin{vmatrix}\cos\theta-\lambda&-\sin\theta\\\sin\theta&\cos\theta-\lambda\end{vmatrix}=0

(\cos\theta-\lambda)^2+\sin^2\theta=0

(\cos\theta-\lambda)^2=-\sin^2\theta

\cos\theta-\lambda=\pm\sqrt{-\sin^2\theta}

\lambda=\cos\theta\pm\sqrt{-\sin^2\theta}

\sin^2\theta\ge0 for all values of \theta, so we need to have \sin\theta=0 in order for \lambda to be real-valued. This happens for

\sin\theta=0\implies\theta=n\pi

where n is any integer, and over the given interval we have \theta=0 and \theta=\pi.

4 0
3 years ago
Solve for k <br> 7k+2m = kr + 4m + 3
professor190 [17]

Answer:

\large\boxed{k=\dfrac{2m+3}{7-r}\ \text{for}\ r\neq7}

Step-by-step explanation:

7k+2m=kr+4m+3\qquad\text{subtract}\ 2m\ \text{from both sides}\\\\7k+2m-2m=kr+4m-2m+3\\\\7k=kr+2m+3\qquad\text{subtract}\ kr\ \text{from both sides}\\\\7k-kr=kr-kr+2m+3\\\\7k-kr=2m+3\qquad\text{distribute}\\\\k(7-r)=2m+3\qquad\text{divide both sides by}\ (7-r)\neq0\\\\k=\dfrac{2m+3}{7-r}

6 0
3 years ago
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