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Dmitriy789 [7]
2 years ago
9

What is the slope of the line that contains these points?

Mathematics
1 answer:
nikklg [1K]2 years ago
3 0

Answer:

3

Step-by-step explanation:

From the table, we know at least 2 ordered pairs. We can use the slope formula on any 2 ordered pairs on the table to get 3.

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Prove the trigonometric identity
Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

Take LCM

1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

Hence proved! :D

4 0
3 years ago
Which of the following graphs would you use if you wanted viewers to see individual data points?
Arturiano [62]
I would either use a histogram or a frequency chart, but histogram is easier and neater 
7 0
3 years ago
Walid is four times as old as Sami . Five years ago,
trapecia [35]

Answer:

he is11 years old cause when he was 1 walked was 5

4 0
2 years ago
How to do this<br> 74^{2n + 1}
nordsb [41]

148ln(74)×74 2n

hop it help

7 0
2 years ago
How many five-letter words (technically, we should call them strings, because we do not care if they make sense) can be formed u
andriy [413]

Total number of five letter strings formed by A,B,C and D with repetitions allowed

={4x4x4x4x4 = 4 power 5 = 1024

Now, fix BAD in a string at one place then we have 2 more places to be filled with 4 letters, total number of such strings

=4x4=16

Here, BAD can be at any of the 3 positions,

Hence the total number of strings with BAD in it

= 3 x 16=48

Now, The total number of strings not containing BAD

=1024-48

=976

Using 26 letters, the number of 5-letter words that can be formed when the letters are different is determined as follows: 26P5 = 26 × 25 × 24 × 23 × 22 = 7883600 different words.

Learn more about five-letter strings here:brainly.com/question/27134945

#SPJ4

8 0
2 years ago
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