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vichka [17]
2 years ago
8

During a game, players can win and lose counters. At the start of the game

Mathematics
1 answer:
Mademuasel [1]2 years ago
5 0
The first step is to calculate what fraction of the counters that Rob has.

Add all the portions together to find the total: 5+6+7= 18
Rob has 5 out of the 18, or 5/18, or 0.278

Next, do the same for the end ratio:
7+9+8= 24 and Rob has 7/24, or 0.292

By comparing his beginning portion (0.278) to his end portion (0.292) it is clear that he has a greater portion of the total counters. Given that the problem states that the number of counters stays the same, Rob must have more counters than he started with.
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Answer:

  1. (0, 4)
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Step-by-step explanation:

In an ordered pair the term before the comma is the x variable and the term after the comma is the y variable.

1.

4x + 3y = 12 . . . . . .(0, _)

here were given the x variable

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4× 0 + 3y = 12

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y = 4

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2.

. . . . . . . (-1, _)

here were given the x variable

4 × -1 + 3y = 12

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3.

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here were given the y variable

finding the other term

4x + 3 × 10 = 12

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4x = 12 - 30

4x = -18

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2x = -9

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The number of students taking classes at RSM Branch A is 1
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Answer:

B = 1320

A= \dfrac54B

Step-by-step explanation:

Let A = number of students at Branch A

Let B = number of students at Branch B

If the number of students taking classes at Branch A is 1/4 more than Branch B, then:

      A=1 \dfrac14B

\implies A= \dfrac54B

If Branch A has 1,650 students, then substitute A = 1650 and solve for B:

\implies 1650= \dfrac54B

\implies 1650 \times 4= 5B

\implies 6600 =5B

\implies B=\dfrac{6600}{5}

\implies B=1320

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Step-by-step explanation:

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