Answer:
Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.
There are three possibilities we need to consider:
Being stopped at both lights
Being stopped at neither light
Being stopped at exactly one light
The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.
Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28
The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18
Step-by-step explanation:
Answer:
1/8(x - 49)
Step-by-step explanation:
When we factor out something, we are basically finding common factors from multiple terms to take out. Example:
ab + ac; factored out: a(b + c)
If we want to factor out 1/8 from 1/8x - 49/8, we simply divide the two terms by 1/8.
The 1/8 cancel out giving us x so:
1/8(x - __)
The next term,

When two fractions divide, you flip the bottom one and multiply them both,

giving us 49.
The answer is: 1/8(x - 49)
Answer:
open
Step-by-step explanation:
Answer:
The second option will cost her less than the first one.
Step-by-step explanation:
In order to solve this problem we will create two functions to represent the cost of the car in function of the miles drove by her.
For the first option we have:

For the second option we have:

Since she intends to drive it for 10,000 miles per year for 6 years, then the total mileage she intends to drive her car is 60,000 miles. Applying this to the formula of each car and we have:


The second option will cost her less than the first one.