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krok68 [10]
3 years ago
10

What is an example of when you would want consistent data and, therefore, a small standard deviation?

Mathematics
1 answer:
steposvetlana [31]3 years ago
8 0

Answer:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

And for the standard deviation we can use the following formula:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And after replace we got:

s = 0.1496

And as we can ee we got a small value for the deviation <1 on this case.

Step-by-step explanation:

For example if we have the following data:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

We see that the data are similar for all the observations so we would expect a small standard deviation

If we calculate the sample mean we can use the following formula:

\bar X=\frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

And for the standard deviation we can use the following formula:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And after replace we got:

s = 0.1496

And as we can ee we got a small value for the deviation <1 on this case.

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An athlete ran 200 meters in 19.19 seconds. Suppose that he ran the first half of that race (around a curve) in 10.75 seconds. H
SOVA2 [1]

The time needed to run the second half of the race is 8.44 s

Step-by-step explanation:

The total distance covered by the athlete during the race is

d = 200 m

And the total time taken to cover this distance is

T = 19.19 s

We also know that the time the athlete needs to cover the first half of the race is

t_1 = 10.75 s

Also, we know that

T=t_1 + t_2

where t_2 is the time the athlete takes to cover the second half of the race.

Re-arranging this equation and susbtituting the values, we find the value of t2:

t_2 = T-t_1 = 19.19-10.75=8.44 s

Learn more about uniform motion:

brainly.com/question/8893949

#LearnwithBrainly

5 0
3 years ago
Please help! thank you~
DanielleElmas [232]

Answer:

i would think u should add them together and that would be 21  but maybe you subtract the two years ago and get 19

Step-by-step explanation:

3 0
4 years ago
The interest on $2,000 for 2 years is $320. What is the simple interest rate?
umka2103 [35]
R = 8%/year

Equation:
r = (1/t)(A/P - 1)
Calculation:
Solving our equation:
r = (1/2)((2320/2000) - 1) = 0.08
r = 0.08

Converting r decimal to R a percentage
R = 0.08 * 100 = 8%/year

The interest rate required to get a total amount, principal plus interest, of $2,320.00 from simple interest on a principal of $2,000.00 over 2 years is 8% per year.
7 0
3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

6 0
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