Question

An athlete ran 200 meters in 19.19 seconds. Suppose that he ran the first half of that race (around a curve) in 10.75 seconds. How long did it take him to run the second half of the race (on a straight track)?

Answer 1

The time needed to run the second half of the race is 8.44 s

Step-by-step explanation:

The total distance covered by the athlete during the race is

d = 200 m

And the total time taken to cover this distance is

T = 19.19 s

We also know that the time the athlete needs to cover the first half of the race is

$t_1 = 10.75 s$

Also, we know that

$T=t_1 + t_2$

where $t_2$ is the time the athlete takes to cover the second half of the race.

Re-arranging this equation and susbtituting the values, we find the value of t2:

$t_2 = T-t_1 = 19.19-10.75=8.44 s$

Learn more about uniform motion:

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