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joja [24]
3 years ago
7

If a couple went out to dinner with there four children and the kids meals cost $11.99 each and the adults meal cost 15.99 each

how much did the family have to pay
Mathematics
1 answer:
Basile [38]3 years ago
5 0
2×$15.99=31.98
+ 4×$11.99=47.96
---------------
$79.94

:. $79.94 is the cost.
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Which set of ordered pairs could be generated by an exponential function?
Ede4ka [16]

Answer:

(1,1), (2, 1/4), (3, 1/9), (4, 1/16)

Step-by-step explanation:

6 0
2 years ago
Pls help! will give thx and 5star and whatever just plss help
Novosadov [1.4K]

Answer:

18. Scalene

19. Quadrilateral

20. option i)

Step-by-step explanation:

18. A triangle whose all the three sides are different is called a scalene Triangle . Where are whose two sides are equal is called an isosceles triangle and whose all the sides are equal is called an equilateral triangle. Here all the sides are of different measurement hence it is a scalene triangle.

19. A polygon containing

3 sides is a triangle

4 sides is Quadrilateral

5 Sides is a Pentagon

6 sides is a Hexagon

8 Sides is Octagon  

Our polygon contains four sides, it is hence a quadrilateral

20.

Option i)

In two congruent figures , the corresponding sides and angles are equal.

corresponding side of  s is side measuring 14 ft and that of t is the side measuring 12 ft

Hence s = 14 and t = 12

corresponding angles of  u is angle measuring 90° and that of r is the angle measuring 90°

Hence ∠u = 90° and ∠r=90°

3 0
3 years ago
Determine the point estimate of the population proportion, the margin of error
ahrayia [7]

Answer:

\hat p=0.645\\\\ME=0.233\\\\x=645 \ individuals

Step-by-step explanation:

-Given the boundaries as 0.412 and 0.878

-\hat p is the point estimate for the population proportion and is calculated as follows:

\hat p=\frac{Upper \ Bound+Lower \ Bound}{2}\\\\=\frac{0.878+0.412}{2}\\\\=0.645\\\\

#The margin of error, ME can be calculated for the confidence intervals using the formula:

ME=\frac{Upper \ Bound-Lower \ Bound}{2}\\\\=\frac{0.878-0.412}{2}\\\\=0.233

#The number of individuals in the sample is the product of the point estimate and population size:

\hat p=\frac{x}{n}\\\\x=\hat pn\\\\=0.645\times 1000\\\\=645

Hence, there are 645 individuals in the sample.

8 0
3 years ago
How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?
MAVERICK [17]

Non-negative integers are positive integers or zero.

1. When x_1=0, then there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=10;
  • x_2=1,\ x_3=9;
  • x_2=2,\ x_3=8;
  • x_2=3,\ x_3=7;
  • x_2=4,\ x_3=6;
  • x_2=5,\ x_3=5;
  • x_2=6,\ x_3=4;
  • x_2=7,\ x_3=3;
  • x_2=8,\ x_3=2;
  • x_2=9,\ x_3=1;
  • x_2=10,\ x_3=0.

In total 11 solutions for x_1=0.

2. For x_1=1, there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=9;
  • x_2=1,\ x_3=8;
  • x_2=2,\ x_3=7;
  • x_2=3,\ x_3=6;
  • x_2=4,\ x_3=5;
  • x_2=5,\ x_3=4;
  • x_2=6,\ x_3=3;
  • x_2=7,\ x_3=2;
  • x_2=8,\ x_3=1;
  • x_2=9,\ x_3=0.

In total 10 solutions for x_1=1.

3. This process gives you

  • for x_1=2 - 9 solutions;
  • for x_1=3 - 8 solutions;
  • for x_1=4 - 7 solutions;
  • for x_1=5 - 6 solutions;
  • for x_1=6 - 5 solutions;
  • for x_1=7 - 4 solutions;
  • for x_1=8 - 3 solutions;
  • for x_1=9 - 2 solutions;
  • for x_1=10 - 1 solution.

4. Add all numbers of solutions:

11+10+9+8+7+6+5+4+3+2+1=66.

Answer: there are 66 possible solutions (with non-negative integer variables)

8 0
3 years ago
Read 2 more answers
It is recommended that there be at least 15.9 square feet of ground space in a garden for every newly planted shrub. A garden is
Helen [10]
The total area of the garden is 37.1 ft x 15 ft = 556.5 sq. ft. It is safe to assume that the area of each shrub is 15.9 sq. ft. The number of shrubs can be calculated by dividing the total area of the garden by the area of each shrub: 556.5 sq. ft. / 15.9 sq. ft. = 35 shrubs.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
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