Count the number of positive integers less than 100 that do not contain any perfect square factors greater than 1.
Possible perfect squares are the squares of integers 2-9.
In fact, only squares of primes need be considered, since for example, 6^2=36 actually contains factors 2^2 and 3^2.
Tabulate the number (in [ ])of integers containing factors of
2^2=4: 4,8,12,16,...96 [24]
3^2=9: 9,18,....99 [11]
5^2=25: 25,50,75 [3]
7^2=49: 49,98 [2]
So the total number of integers from 1 to 99
N=24+11+3+2=40
=>
Number of positive square-free integers below 100 = 99-40 = 59
You would put in 12 for x since there are 12 months in a year. Then you would multiply 12 by 35, and add 70.
Answer:
37, 700, 000
Step-by-step explanation:
377(10,000) = 377 x 10,000
= 37, 700, 000
an easy way to see it is to just add the number of zeros from 10,000 to 377. since there are four zeros, you put four zeros behind 377.
<em><u>[it's not mathematical but it helps u see the answer better. and it only works with numbers that start with 1]</u></em>
Answer:
Step-by-step explanation:
Ive already explained this somebody else asked if you find it you will have the answer
