Answer: Choice A
m = undefined
point (-2,5)
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Explanation:
The equation x = -2 describes a vertical line in which every point on this line has x coordinate -2. Two points on this line are (-2,0) and (-2,1)
Another point on this line is (-2,5) since this also has x coordinate -2.
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All vertical lines have undefined slope.
Let's pick two points such as (-2,0) and (-2,1) and find the slope through them
m = (y2-y1)/(x2-x1)
m = (1-0)/(-2-(-2))
m = (1-0)/(-2+2)
m = 1/0
m = undefined, since we cannot divide by zero.
Answer:
82.8 cm measured to the nearest tenth of 80cm.
Answer:
8. 1
7. 9
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6. 2
5. 2
4. 1
3. 18
2. 10000
1. 25
Step-by-step explanation:
According to the Order of Operations, if there are any <em>grouping symbols</em>, you take care of them first. Second, you deal with any <em>indices</em><em>,</em> roots, or <em>powers</em><em>.</em><em> </em>Third comes the evaluation of<em> </em><em>Division</em><em> </em><em>&</em><em> </em><em>Multiplication</em><em> </em>from left to right in the order of which you see them appear. The fourth and final step is the evaluation of <em>Subtraction</em><em> </em><em>&</em><em> </em><em>Addition</em><em> </em>from left to right in the order of which you see them appear.
** I was writing down ALL my writing down all my calculations up until a computer glitch caused my work to go <em>work-rupt</em><em>,</em><em> </em>if<em> </em>you<em> </em>know what I mean.
I apologize for the inconvenience, I hope this explanation helps you out alot, and as always, I am joyous to assist anyone at any time.
Answer: h=(D²-s)/3
Step-by-step explanation: D² =3h+s
Subtract a from both sides of the equation
D²-s =3h+s-s
Simplifying,
D²-s =3h
Divide both sides by 3( to isolate 'h')
(D²-s)/3 =3h/3
Simplifying,
(D²-s)/3 =h
Hence, h= (D²-s)/3
Hope it helps!
Answer:
All of the above
Step-by-step explanation:
dy/dt = y/3 (18 − y)
0 = y/3 (18 − y)
y = 0 or 18
d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)
d²y/dt² = dy/dt (-y/3 + 6 − y/3)
d²y/dt² = dy/dt (6 − 2y/3)
d²y/dt² = y/3 (18 − y) (6 − 2y/3)
0 = y/3 (18 − y) (6 − 2y/3)
y = 0, 9, 18
y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.
y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.
