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Elena-2011 [213]
3 years ago
6

Ini bagaimana ya? Tolong caranya dong.

Mathematics
1 answer:
zaharov [31]3 years ago
8 0

Answer:

?

Step-by-step explanation:

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What is the probability of flipping two coins at the same time and getting heads on both coins?
Romashka-Z-Leto [24]
According to me the probability is 1/4, because there are 4 possible outcomes when two coins are flipped - TT, TH, HT, HH. 

<span>Also, would it matter if the coins are flipped one after other rather than together</span>
5 0
3 years ago
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Ap calc multiple choice question; attached below<br> please explain how, please!
anygoal [31]

Answer:

C. \frac{f(b)-f(1)}{b-1}=20

General Formulas and Concepts:

<u>Calculus</u>

  • Mean Value Theorem (MVT) - If f is continuous on interval [a, b], then there is a c∈[a, b] such that  f'(c)=\frac{f(b)-f(a)}{b-a}
  • MVT is also Average Value

Step-by-step explanation:

<u>Step 1: Define</u>

f(x)=e^{2x}

f'(c) = 20

Interval [1, b]

<u>Step 2: Check/Identify</u>

Function [1, b] is continuous.

Derivative [1, b] is continuous.

∴ There exists a c∈[1, b] such that f'(c)=\frac{f(b)-f(a)}{b-a}

<u>Step 3: Mean Value Theorem</u>

  1. Substitute:                    20=\frac{ f(b)-f(1)}{b-1}
  2. Rewrite:                        \frac{ f(b)-f(1)}{b-1}=20

And we have our final answer!

5 0
3 years ago
How many more pumpkins have a mass between 9 and 12 kg than between 0 and 3 kg?
KengaRu [80]

Answer:

According to the graph, there are 6 pumpkins with the mass of 9kg to 12kg and 4 pumpkins with the mass of 0kg to 3kg.

In order to find how many pumpkins more, you have to subtract it so it will be 6 pumpkins - 4 pumpkins = 2 pumpkins.

Therefore, there are 2 more pumpkins with the mass of 9 to 12kg compared to the pumpkins with the mass of 0 to 3kg.

5 0
4 years ago
5,ooo invested 5 years 3% interest compounded continuously
galben [10]
A=pe^rt

A future value
P principle 5000
R interest rate 3/100 =0.03
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6 0
3 years ago
HELPPPPP PLEASEE
Natasha2012 [34]
On graph paper, simple plot these two points. Then draw a line that hits both of these points. Then you will find that the line you drew never entered the first quadrant (the one on the top right side)
8 0
3 years ago
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