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vagabundo [1.1K]
3 years ago
13

What is the truth value for the following conditional statement?

Mathematics
1 answer:
krok68 [10]3 years ago
3 0
The answer is TT=T because why will it be a true or false
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Write the explicit formula that represents the geometric sequence -2,8,-32,128.
Dmitriy789 [7]

Answer:

a_{n} = - 2(-4)^{n-1}

Step-by-step explanation:

The n th term ( explicit formula ) for a geometric sequence is

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Here a = - 2 and r = 8 ÷ - 2 = - 4, thus

a_{n} = - 2(-4)^{n-1}

5 0
3 years ago
You work 12 hours for $69. Find the rate per hour.
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5.75 an hour good luck lollllllll
6 0
3 years ago
Solve for y: x=5y-3
kobusy [5.1K]
X=5y-3
-5y=-x-3
5y=x+3
y=x/5 + 3/5
7 0
3 years ago
Read 2 more answers
Katie is k years old. Harry is 4 years older than Katie. Rachel is twice as old as Harry. If you add together the ages of Katie,
vichka [17]
K+(k+4)+2k=36
4k+4=36
4k=36-4
4k=32
k=8
5 0
4 years ago
Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm prett
valentinak56 [21]

Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

With 5 shoots, the probability of making at least one is \frac{211}{243}, hence the probability of making none, P(X = 0), is \frac{232}{243}, hence:

(1 - p)^5 = \frac{232}{243}

\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}

1 - p = 0.9908

p = 0.0092

Then, with 6 shoots, the parameters are:

n = 6, p = 0.0092.

The probability that at least two of them make it inside the recycling bin is:

P(X \geq 2) = 1 - P(X < 2)

In which:

[P(X < 2) = P(X = 0) + P(X = 1)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461

P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012

0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

7 0
2 years ago
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