The dog is leashed to a fixed point, the leash has a length of 20 ft, therefore he can rotate around that point at the maximum distance equal to the length of the leash. This pattern forms a circle, but there is an obstruction, which is the corner of the house. This obstruction takes an arc of the original circle, so the running area of the dog is the area of the whole circle minus the area of the arc formed by the corner of the house.

$\text{dog's area} = \text{circle's area} - \text{arc's area}\\\\\text{dog's area} = pi*(20^2) - \frac{90}{360}*pi*(20^2)\\\\\text{dog's area} = \frac{270}{360}*pi*(400)\\\\\text{dog's area} = 942.477\text{ feet}^2$

The dog's running area is approximately 942 feet².

3 0

3 years ago

Which expression is equivalent -4×4×4×4×4×4×4×4?<br>

WITCHER [35]

Answer:

$-\underbrace{4\times4\times4\times4\times4\times4\times4\times4}_{8}=-4^8$

4 0

3 years ago

Read 2 more answers

Which value of x makes the equation 1.25(6x - 20) = 50 true?

bixtya [17]

D. X = 10

6x-20= 40

6x=40+20

6x=60

X=10

4 0

3 years ago

Please help me. thanks.

Rama09 [41]

$~~~\text{Area of triangle} = \dfrac 12 \times \text{Base} \times \text{Height}\\\\\implies 10 = \dfrac 12 \times 5 \times w\\\\\implies w =\dfrac{20}5 \\\\\implies w = 4 ~cm$

8 0

2 years ago

Read 2 more answers