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Gnesinka [82]
3 years ago
6

2 po

Mathematics
1 answer:
Lyrx [107]3 years ago
8 0

Answer:

Step-by-step explanation:

Girls:Total number of people

89:235

89:47

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HELPPPPPPP PLEASEEEEEEEEEEE
Inessa [10]

Answer:

y=-1

Step-by-step explanation:

it is a straight line graph with no gradient therefore no X value. It crosses the y axis at -1

8 0
3 years ago
If log a=3 log b-2 log c, find an expression for a that does not involve logarithms​
photoshop1234 [79]

Assuming that b>0 and c>0:

log(a)=3×log(b)-2×log(c)=

log(b³)-log(c²)=

log(b³/c²)

Hence a=b³/c²

7 0
3 years ago
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
Which of the following linear relationships is NOT also a proportional relationship?
katen-ka-za [31]

The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x  , y = - (1/2)x  .

A linear relationship in the form of y = mx + c is said to be a proportional relationship when c = 0  .

in the question

Part(a)

the equation is  y = (2)x - 3

on comparing it with y = mx + c , we get c = -3 , which is not 0 .

So , it is not a proportional relationship .

Part(b)

the equation is  y = (-2)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Part(c)

the equation is  y = (3/5)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Part(d)

the equation is  y = - (1/2)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Therefore, The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x  , y = - (1/2)x  , that are options (b) , (c) and (d) .

The given question is incomplete , the complete question is

Which of the following linear relationships is NOT also a proportional relationship?

(a) y = (2)x - 3

(b) y = (-2)x

(c) y = (3/5)x

(d) y = - (1/2)x

Learn more about Proportionality here

brainly.com/question/14967814

#SPJ1

8 0
1 year ago
A members-only speaker series allows people to join for $20 and then pay $1 for every
Paha777 [63]

Answer:

30

Step-by-step explanation:

3 0
2 years ago
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