Answer:
The solutions to the quadratic equations are:
Step-by-step explanation:
Given the function
substitute y = 0 in the equation to determine the zeros
Switch sides
Add 4 to both sides
Simplify
Rewrite in the form (x+a)² = b
But, in order to rewrite in the form x²+2ax+a²
Solve for 'a'
2ax = -6x
a = -3
so add a² = (-3)² to both sides
Apply perfect square formula: (a-b)² = a²-2ab+b²
solve
Add 3 to both sides
Simplify
now solving
Add 3 to both sides
Simplify
Thus, the solutions to the quadratic equations are:
It's C)
the graph is decrasing, so the variable rate is negative (-2/3)
the rest was quite easy, you just take a look at where the graph cuts the y-axis and determine the rest from the rate of going up or down (increase/decrease)
The possible coordinate of point a is (6,4)
Answer:
no answer sorry
Step-by-step explanation:
no answer sorry
Answer:
The transformation is " a horizontal translation 4 units to the right " ⇒ (d)
Step-by-step explanation:
Let us revise the translation of a function
- If the function f(x) translated horizontally to the right by h units, then its image is g(x) = f(x - h)
- If the function f(x) translated horizontally to the left by h units, then its image is g(x) = f(x + h)
- If the function f(x) translated vertically up by k units, then its image is g(x) = f(x) + k
- If the function f(x) translated vertically down by k units, then its image is g(x) = f(x) - k
Let us look at the graph and choose some points on the f(x) and find their images on y
∵ Point (1, 2) lies on f(x)
∵ Point (5, 2) lies on y
∵ Point (3, 8) lies on f(x)
∵ Point (7, 8) lies on y
→ There is no change in the y-coordinates of the points, the change
only in the x-coordinates
∴ The translation is horizontally
∵ 5 - 1 = 4 units ⇒ positive value means to right
∴ f(x) is translated 4 units to the right
∴ The answer is " a horizontal translation 4 units to the right " (d)
