Answer:
Fraction of the garden used = 
Step-by-step explanation:
The fifth graders to plant a butterfly garden.
We are given that
Clover grows in ½ of the garden
Daisies grow in ¼ of the garden
Coneflowers grow in ⅛ of the garden
milkweed grows in ⅛ of the garden
The fifth graders notice that the butterflies land on the clover and milkweed.
We are asked to find out the fraction of the garden that the butterflies used.
Fraction of the garden used = clover + milkweed
Fraction of the garden used = 
The LCM of 2 and 8 is 8
Fraction of the garden used = 
Fraction of the garden used = 
Therefore, the butterflies used
fraction of the garden.
Answer:
Final answer is 1/3.
Step-by-step explanation:
Question says that Mrs Jenkins picked some tomatoes from her garden. She used 5/9 of the tomatoes to make pasta sauce. After that she used 3/4 of the remainder to make a salad. Now we need to find about what fraction of the tomatoes did Mrs Jenkins use to make the salad.
As she used 5/9 of the tomatoes to make pasta sauce.
Now remaining amount of tomatoes = 1- 5/9 = 9/9 -5/9 = 4/9
Then she used 3/4 of the remainder to make a salad. So fraction of the tomatoes did Mrs Jenkins use to make the salad = (4/9)(3/4)=12/36=1/3
Hence final answer is 1/3.
Answer:
0.281 = 28.1% probability a given player averaged less than 190.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A bowling leagues mean score is 197 with a standard deviation of 12.
This means that 
What is the probability a given player averaged less than 190?
This is the p-value of Z when X = 190.



has a p-value of 0.281.
0.281 = 28.1% probability a given player averaged less than 190.
The number beside the letter . for example 6x, 6 would be the variable