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Zarrin [17]
3 years ago
14

A certain smart phone game app allows the player, once a day, to spin a wheel with 8 different sections. Seven of the sections c

ontain a small prize and one of the sections is the grand prize, in which the player wins all of the other seven prizes. The makers of the game claim that the wheel has an equally likely probability of landing on each section. Andraya has played the game for several months and believes that the grand prize occurs less often than the game makers claim.
Required:
What would be appropriate hypotheses for the Andraya to test?
Mathematics
1 answer:
prisoha [69]3 years ago
5 0

Answer:

The appropriate hypothesis set for Andraya to test is:

H_0: p = 0.125

H_1: p < 0.125

Step-by-step explanation:

The makers of the game claim that the wheel has an equally likely probability of landing on each section.

That is, the makers claim that the probability of earning the grand prize is:

p = \frac{1}{8} = 0.125

Andraya has played the game for several months and believes that the grand prize occurs less often than the game makers claim.

At the null hypothesis, we test if it happens as often as the makers claim, that is, the proportion is 0.125. So

H_0: p = 0.125

At the alternate hypothesis, we test if it happens less ofter than the makers claim, that is, the proportion is less than 0.125. So

H_1: p < 0.125

The appropriate hypothesis set for Andraya to test is:

H_0: p = 0.125

H_1: p < 0.125

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sergij07 [2.7K]

30 and 13


x-y=17 and x+y=43

x=17+y and x=43-y, so 17+y=43-y

so y=13

43-13=30, so x=30 and y=13

8 0
3 years ago
Please solve and explain the question below
solong [7]

Answer:

OPTION A

Step-by-step explanation:

To find the table substitute the points on the given function and compare the values.

The given function is: $ y = x^2 + 2 $.

OPTION A:

(i) When x = -2

LHS = y = 6.

RHS = (-2)² + 2 = 4 + 2 = 6.

LHS = RHS

(ii) When x = -1

LHS = y = 3

RHS = (-1)² + 2 = 1 + 2 = 3.

LHS = RHS

(iii) When x = 0

LHS = y = 2

RHS = 0² + 2 = 2.

LHS = RHS

(iv) When x = 1

LHS = y = 3

RHS = (1)² + 2 = 1 + 2 = 3.

LHS = RHS

(v) When x = 2

LHS = y = 6

RHS = (2)² + 2 = 4 + 2 = 6

LHS = RHS

OPTION B:

(i) When x = -2

LHS = y = -2

RHS = (-2)² + 2 = 6

LHS \neq RHS

OPTION B is eliminated.

OPTION C:

(i) When x = -2

Using the same reason as OPTION B this option is eliminated as well.

So, OPTION A is the correct answer.

5 0
3 years ago
Find the difference or type impossible [9 -1] [4 3] [2 -3] [5 0]
IrinaK [193]

The difference based on the numbers given is -80.

<h3>How to compute the difference?</h3>

The information given illustrates that the difference will be:

= (9 - 1) - (43) - (2 - 3) - 50

= 8 - 43 - (-1) - 50

= 8 - 43 + 1 - 50

= -80

Therefore, the difference or subtraction among the numbers given is -80.

Learn more about difference on:

brainly.com/question/148825

#SPJ1

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1 year ago
Rewrite the expression with a rational exponent as a radical expression.
Vilka [71]

Answer:

\sqrt{5}

Step-by-step explanation:

we know that

The "power rule" tells us that to raise a power to a power, just multiply the exponents

so

(a^{m})^{n}=a^{m*n}

we have

(5^{\frac{3}{4}})^{\frac{2}{3}}

Applying the "power rule"

(5^{\frac{3}{4}})^{\frac{2}{3}}=5^{\frac{3}{4}*\frac{2}{3}}=5^{\frac{1}{2}}=\sqrt{5}

5 0
3 years ago
What is 90times345 need it now
Ivanshal [37]
90*345=
31050
Hope i helped.
6 0
3 years ago
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