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Zarrin [17]
3 years ago
14

A certain smart phone game app allows the player, once a day, to spin a wheel with 8 different sections. Seven of the sections c

ontain a small prize and one of the sections is the grand prize, in which the player wins all of the other seven prizes. The makers of the game claim that the wheel has an equally likely probability of landing on each section. Andraya has played the game for several months and believes that the grand prize occurs less often than the game makers claim.
Required:
What would be appropriate hypotheses for the Andraya to test?
Mathematics
1 answer:
prisoha [69]3 years ago
5 0

Answer:

The appropriate hypothesis set for Andraya to test is:

H_0: p = 0.125

H_1: p < 0.125

Step-by-step explanation:

The makers of the game claim that the wheel has an equally likely probability of landing on each section.

That is, the makers claim that the probability of earning the grand prize is:

p = \frac{1}{8} = 0.125

Andraya has played the game for several months and believes that the grand prize occurs less often than the game makers claim.

At the null hypothesis, we test if it happens as often as the makers claim, that is, the proportion is 0.125. So

H_0: p = 0.125

At the alternate hypothesis, we test if it happens less ofter than the makers claim, that is, the proportion is less than 0.125. So

H_1: p < 0.125

The appropriate hypothesis set for Andraya to test is:

H_0: p = 0.125

H_1: p < 0.125

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In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
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Answer:

210

Step-by-step explanation:

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Medals in dance = 25

Medals in music = 212

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Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

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To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

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3 years ago
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