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3 years ago

Which pair of undefined terms is used to define a ray?

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

7 0

Answer:

A point and line is used to define a ray.

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Which expressions are equivalent to 5(-2k-3)+2k

bulgar [2K]

Answer:

-8k - 15

Step-by-step explanation:

5(-2k-3)+2k

At first, we will break the parenthesis. To break that, we will multiply the value inside the parenthesis by the adjacent number, that is 5. Again, we have to consider the Algebraic operation (Golden rule) -

[(-) x (-) = (+); (+) x (-) = (-)]

Therefore, since there is a minus sign in each of the value inside the parenthesis, the result will be minus as 5 is a positive integer.

or, -5*(2k) - (5*3) + 2k

or, -10k - 15 + 2k

or, -8k - 15 (after the deduction)

The answer is = -8k - 15

6 0

3 years ago

What's 7 times 11 in joke

Vesna [10]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

About 36,100,000 households in the U.S. have cats and about 43,300,000 households have dogs. About how may more households dogs

Svetllana [295]

Theres about a 7,200,000 difference between household dogs vs household cats

5 0

3 years ago

Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul

natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

$\bf B=\displaystyle\frac{L}{4\pi d^2}$

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of Alpha Centauri A is

$\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728$

According to the inverse square law for light intensity

$\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}$

where

$\bf I_1=$ light intensity at distance $\bf d_1$

$\bf I_2=$ light intensity at distance $\bf d_2$

Let $\bf d_2$ be the distance we would have to place the 50-watt bulb, then replacing in the formula

$\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}$

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0

3 years ago

Whose method is correct?

boyakko [2]

Answer: Jaleel´s method is correct and the right option is option number D

Step-by-step explanation:

its because 2(x-2)

= 2x-4

note 2 is multiplied with both x and -2!

4 0

3 years ago