3 years ago

Unit 4.2 math 8th grade

Mathematics

2 answers:

UkoKoshka [18]3 years ago

7 0

Answer:

So?

Step-by-step explanation:

cluponka [151]3 years ago

3 0

Answer: ok but what is your question lol

Step-by-step explanation:

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What is the roots of f(x)=-x^2-6x-14

Nutka1998 [239]

Answer:

$x=-3\pm i \sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Algebra II

Imaginary roots: √-1 = i

Step-by-step explanation:

Step 1: Define function

f(x) = -x² - 6x - 14

Step 2: Set up

Set equation equal to 0: -x² - 6x - 14 = 0
Factor out -1: -(x² + 6x + 14) = 0
Divide both sides by -1: x² + 6x + 14 = 0

Step 3: Define variables

a = 1

b = 6

c = 14

Step 4: Find roots

Substitute: $x=\frac{-6\pm\sqrt{6^2-4(1)(14)} }{2(1)}$
Exponents: $x=\frac{-6\pm\sqrt{36-4(1)(14)} }{2(1)}$
Multiply: $x=\frac{-6\pm\sqrt{36-56} }{2}$
Subtract: $x=\frac{-6\pm\sqrt{-20} }{2}$
Factor: $x=\frac{-6\pm\sqrt{-1} \sqrt{20} }{2}$
Simplify: $x=\frac{-6\pm2i \sqrt{5} }{2}$
Factor: $x=\frac{2(-3\pm i \sqrt{5} )}{2}$
Divide: $x=-3\pm i \sqrt{5}$

8 0

3 years ago