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aksik [14]
3 years ago
15

Evaluate fog and gof if f(x)=5x-8 and g(x)= x^3

Mathematics
1 answer:
DerKrebs [107]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

note that f ○ g = f(g(x))

To evaluate substitute x = x³ into f(x)

f(g(x)) = f(x³) = 5x³ - 8

In the same way

g ○ f = g(f(x))

To evaluate substitute x = 5x - 8 into g(x)

g(f(x)) = g(5x - 8) = (5x - 8)³


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If (14,25) and (9,-10) are two anchor points on a trend line, then find the equation of the line.
posledela

Answer:

y= 7x-73

Step-by-step explanation:

the equation form is y=mx+c where m is the slope and c a constant

m= (25-(-10))/14-9 = 35/5 = 7

so y= 7x+c

replace x and y by 14 and 25 respectively

25 = 7*14+c

c= 25-7*14

c = -73

so y= 7x-73

3 0
3 years ago
Over which interval is the graph of f(x) = one-halfx2 + 5x + 6 increasing?
kaheart [24]

Answer:

\large\boxed{x\in[-5,\ \infty)}

Step-by-step explanation:

f(x)=\dfrac{1}{2}x^2+5x+6\\\\\text{The coeficient of}\ x^2\ \text{is the positive number. Therefore the parabola is op}\text{en up}.\\\\\text{If a parabola op}\text{en up, then the graph increasing in interval}\ (h,\ \infty),\\\text{and decreasing in interval}\ (-\infty,\ h).\ \text{Where}\ h\ \text{is a first coordinate of a vertex.}\\\\\text{For}\ y=ax^2+bx+c,\ h=\dfrac{-b}{2a}.\\\\\text{We have}\ a=\dfrac{1}{2}\ \text{and}\ b=5.\ \text{Substitute:}\\\\h=\dfrac{-5}{2\left(\frac{1}{2}\right)}=-\cdot\dfrac{5}{1}=-5.

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What is the undefined variable in this equation (6x2 +3x) ÷ (3x) simplified 3x + 1
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8. The expression below is evaluated when x = 9, y = 3,
Reptile [31]

Answer:

64

Step-by-step explanation:

First of all substitute the values to where ever you see their corresponding variables to make them multiply.

x = 9

y = 3

z = 2

so we get

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then the it's will be

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which is

72 - 14 + 6

finally we get

64

4 0
2 years ago
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