Answer:
Therefore the Correct option is First one
SAS, ∠A ≅ ∠C, AB ≅ CB , ∠ABD ≅ ∠CBD
.
Step-by-step explanation:
Given:
∠BDA ≅ ∠BDC
AD ≅ CD
TO Prove
ΔADB ≅ ΔCDB
Proof:
In ΔADB and ΔCDB
AD ≅ CD ....……….{Given}
∠BDA ≅ ∠BDC …………..{Given}
BD ≅ BD ....……….{Reflexive Property}
ΔADB ≅ ΔCDB ….{By Side-Angle-Side Congruence Postulate}
∴ ∠A ≅ ∠C ......{Corresponding Parts of Congruent Triangle are Congruent}
AB ≅ CB ......{Corresponding Parts of Congruent Triangle are Congruent}
∠ABD ≅ ∠CBD {Corresponding Parts of Congruent Triangle are Congruent}
For this case we have that by definition, the domain of a function, is given for all the values for which the function is defined.
We have:

The given function is not defined when the denominator is equal to zero. That is to say:

To find the roots we factor, we look for two numbers that when multiplied give as a result "8" and when added as a result "-6". These numbers are:

Thus, the factored polynomial is:

That is to say:

Makes the denominator of the function 0.
Then the domain is given by:
All real numbers, except 2 and 4.
Answer:
x |x≠2,4
Perimeter P=2L+2W
P=24
L=w+4
P=2(w+4)+2w
24=2w+8+2w
24=8+4w
16=4w
w=4
L=8