Answer:Which four inequalities can be used to find the solution to this absolute value inequality?3+2|x-11 <9
2(x - 1) <-3
x-1 <9
X-1 >-9
-2(x - 1) > 3
x-1-3
X-1 <3
Step-by-step explanation:
Answer:
11∗2+13∗4+15∗6+⋯+199∗100=?
=(1−12)+(13−14)+(15−16)+⋯+(199−1100)
=(1+13+15+17+⋯+199)−(12+14+16+⋯+1100)
=(1+13+15+17+⋯+199)−12(1+12+13+⋯+150)
=∑k=15012k−1−∑k=15012k
Continue further.
They have 3 packages so p=3
so N(p) = 90p
therefore N(3) = 270
they cannot feed more than 270 people so the range must be N(p)>270
Ramp² = 19² + 4²
ramp² = 361 + 16
ramp² = 377
ramp =
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<span>
19.42
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Incidentally, the angle of the ramp would be
tan (angle) = 4 / 19
tan (angle) =
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<span>
0.210526315789474
arc tan </span></span></span><span>(0.210526315789474) = 11.889 Degrees
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Answer:
The diameter of the pizza = 14 in
Radius of the pizza = (14/2)in = 7in
Area of a whole pizza =
πr^2
=( 22/7 × 7^2)in^2
=( 22/7 × 49)in^2
154 in^2
Area of a half pie =( 1/2 × 154)in^2 = 77in^2
Area of one of 8 slices = (1/8 × 154)in^2 = 19.25in^2
Hope it helps