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marta [7]
2 years ago
13

Find the difference. 8x-(12x^2+5x)=

Mathematics
1 answer:
valentinak56 [21]2 years ago
4 0

Answer:

− 24 x − 12 h +3

Step-by-step explanation:

8x-(12x^2+5x)

<em>difference</em>

<u>f ( x + h )   and   f ( x ) , and plug these values into the difference quotient formula</u>

− 24 x − 12 h +3

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Let X1, . . . ,Xn ∈ R be independent random variables with a common CDF F0. Let Fn be their ECDF and let F be any CDF. If F = Fn
Georgia [21]

Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof that: Let X_1, X_2, ...X_n \in R be independent random variables with a common CDF F_0. Let F_n be their ECDF and let F any CDF. If F \neq F_n then L(F)

Proof

Let z_a different values in the set {X_1,X_2,...,X_n}} and we can assume that n_j \geq 1 represent the number of X_i that are equal to z_j.

We can define p_j = F(z_j) +F(z_j-) and assuming the probability \hat p_j = \frac{n_j}{n}.

For the case when p_j =0 for any j=1,....,m then we have that the L(F) =0< L(F_n)

And for the case when all p_j >0 and for at least one p_j \neq \hat p_j we know that log(x) \leq x-1 for all the possible values x>0. So then we can define the following ratio like this:

log (\frac{L(F)}{L(F_n)}) = \sum_{j=1}^m n_j log (\frac{p_j}{\hat p_j})

log (\frac{L(F)}{L(F_n)}) = n \sum_{j=1}^m \hat p_j log(\frac{p_j}{\hat p_j})

log (\frac{L(F)}{L(F_n)}) < n\sum_{j=1}^m \hat p_j (\frac{p_j}{\hat p_j} -1)

So then we have that:

log (\frac{L(F)}{L(F_n)}) \leq 0

And the log for a number is 0 or negative when the number is between 0 and 1, so then on this case we can ensure that L(F) \leq L(F_n)

And with that we complete the proof.

8 0
3 years ago
Is 30 a multiple of .5
ahrayia [7]

yes becasue it is 30

,

0.5 hope this correct please don't delete this am trying to help can i get a brainliest


4 0
3 years ago
Read 2 more answers
The ground temperature at an airport is 10 °C. The temperature decreases by 5.4 °C for every increase of 1 kilometer above the g
Paraphin [41]

The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Given that,

  • The ground temperature at the airport is 10 °C.
  • The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.

Based on the above information, the temperature outside should be

The decrease in the temperature should be

= 5.4×5

= 27°C

Now the final temperature is

= 10 - 27

= -17°C

Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Learn more: brainly.com/question/20459283

5 0
2 years ago
What describes the components of the arithmetic sequence formula?
AVprozaik [17]
a_{n}=a_{1}+d(n-1)

an is the 'nth' term
a1 is first term
d=common difference (found by doing a_{n}-a_{n-1})
n=numerical representation of which term
6 0
3 years ago
Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th
amm1812
(5,22.45),(7,25.45)
slope = (25.45 - 22.45) / (7 - 5) = 3/2 or 1.5

y = mx + b
slope(m) = 1.5
use either of ur points...(5,22.45)...x = 5 and y = 22.45
now sub and find b
22.45 = 1.5(5) + b
22.45 = 7.5 + b
22.45 - 7.5 = b
14.95 = b

so ur equation is : y = 1.5x + 14.95.......this means that each quart of oil costs $ 1.50 and the labor fee costs $ 14.95
3 0
3 years ago
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