All categories

3 years ago

Find the difference. 8x-(12x^2+5x)=

Mathematics

1 answer:

valentinak56 [21]3 years ago

4 0

Answer:

− 24 x − 12 h +3

Step-by-step explanation:

8x-(12x^2+5x)

<em>difference</em>

<u>f ( x + h ) and f ( x ) , and plug these values into the difference quotient formula</u>

− 24 x − 12 h +3

You might be interested in

Let X1, . . . ,Xn ∈ R be independent random variables with a common CDF F0. Let Fn be their ECDF and let F be any CDF. If F = Fn

Georgia [21]

Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof that: Let $X_1, X_2, ...X_n \in R$ be independent random variables with a common CDF $F_0$ . Let $F_n$ be their ECDF and let F any CDF. If $F \neq F_n$ then $L(F)$

Proof

Let $z_a$ different values in the set { $X_1,X_2,...,X_n}$ } and we can assume that $n_j \geq 1$ represent the number of $X_i$ that are equal to $z_j$ .

We can define $p_j = F(z_j) +F(z_j-)$ and assuming the probability $\hat p_j = \frac{n_j}{n}$ .

For the case when $p_j =0$ for any $j=1,....,m$ then we have that the $L(F) =0< L(F_n)$

And for the case when all $p_j >0$ and for at least one $p_j \neq \hat p_j$ we know that $log(x) \leq x-1$ for all the possible values $x>0$ . So then we can define the following ratio like this:

$log (\frac{L(F)}{L(F_n)}) = \sum_{j=1}^m n_j log (\frac{p_j}{\hat p_j})$

$log (\frac{L(F)}{L(F_n)}) = n \sum_{j=1}^m \hat p_j log(\frac{p_j}{\hat p_j})$

$log (\frac{L(F)}{L(F_n)}) < n\sum_{j=1}^m \hat p_j (\frac{p_j}{\hat p_j} -1)$

So then we have that:

$log (\frac{L(F)}{L(F_n)}) \leq 0$

And the log for a number is 0 or negative when the number is between 0 and 1, so then on this case we can ensure that $L(F) \leq L(F_n)$

And with that we complete the proof.

8 0

3 years ago

Is 30 a multiple of .5

ahrayia [7]

yes becasue it is 30

0.5 hope this correct please don't delete this am trying to help can i get a brainliest

4 0

3 years ago

Read 2 more answers

The ground temperature at an airport is 10 °C. The temperature decreases by 5.4 °C for every increase of 1 kilometer above the g

Paraphin [41]

The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Given that,

The ground temperature at the airport is 10 °C.
The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.

Based on the above information, the temperature outside should be

The decrease in the temperature should be

= 5.4×5

= 27°C

Now the final temperature is

= 10 - 27

= -17°C

Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Learn more: brainly.com/question/20459283

5 0

2 years ago

What describes the components of the arithmetic sequence formula?

AVprozaik [17]

$a_{n}=a_{1}+d(n-1)$

an is the 'nth' term
a1 is first term
d=common difference (found by doing $a_{n}-a_{n-1}$ )
n=numerical representation of which term

6 0

3 years ago

Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th

amm1812

(5,22.45),(7,25.45)
slope = (25.45 - 22.45) / (7 - 5) = 3/2 or 1.5

y = mx + b
slope(m) = 1.5
use either of ur points...(5,22.45)...x = 5 and y = 22.45
now sub and find b
22.45 = 1.5(5) + b
22.45 = 7.5 + b
22.45 - 7.5 = b
14.95 = b

so ur equation is : y = 1.5x + 14.95.......this means that each quart of oil costs $ 1.50 and the labor fee costs $ 14.95

3 0

3 years ago