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harina [27]
3 years ago
11

The ratio of Tv commercial mins to scheduled show time mins is 6 to 24 how many mins of commercial time will be seen during a 2

hour viewing
( please explain what to do thank you)
Mathematics
1 answer:
vodomira [7]3 years ago
3 0
Well first set up the first ratio as 6/24. That is commercial mins over show time mins. Then to keep the units the same convert 2 hours into minutes which would be 120 minutes. Then set up your next ratio as x/120 since you’re trying to find the commercial minutes. Then cross multiply so that it’s 24x=720 and then x=30 and that’s the amount of commercial minutes for 2 hours.
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Which expression is equivalent to <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B10%20%7Bx%7D%5E%7B5%7D%
solong [7]

Answer:

\frac{\sqrt[3]{5} }{3x}

Step-by-step explanation:

6 0
3 years ago
Transform the equation to isolate x: ax = bx 1. How is the value of x related to the difference of a and b?
cestrela7 [59]

Answer:

The value of x is reciprocal of the difference of a and b.

Step-by-step explanation:

We are given the equation, ax=bx+1

On simplifying, we get,

ax=bx+1

i.e. ax-bx=1

i.e. (a-b)x=1

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So, we get,

The value of x is \frac{1}{a-b}.

That is, the value of x is reciprocal of the difference of a and b.

5 0
3 years ago
Read 2 more answers
the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width
dolphi86 [110]

Answer:

  • Length = 17 inches

  • Width = 12 inches

⠀

Step-by-step explanation:

⠀

As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

⠀

Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

⠀

Now, <u>According to the Question :</u>

⠀

{\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( 2x + 5  )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 58  - 10}}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 48}}}}

⠀

{\longrightarrow \qquad { {\sf{ x =  \dfrac{48}{4} }}}}

⠀

{\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\:  \:  \bigstar

⠀

Therefore,

  • The width of the rectangle is 12 inches .

⠀

Now, We are to find the length of the rectangle:

{\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}

⠀

Therefore,

  • The length of the rectangle is 17 inches .

⠀

8 0
2 years ago
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Answer:

The slope of the line is -5

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Papessa [141]
The answer is 5.2
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4 0
3 years ago
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