5. Which of the following situations could be solved using the equation 3m + 5 = 11? Select two

Mathematics

2 answers:

Kruka [31]2 years ago

8 0

Answer:

B and A should be the answer I believe because 3m+5=11 which would be 11-5 because you have to change 5 from a positive and that would equal 6 and 6 divide by 3 is 2.

Volgvan2 years ago

6 0

Answer:

Step-by-step explanation:

Box in your 3m. Subtract 5 from both sides. You get 6. Now, divide 6 by 3 which is boxxed and you get 2.

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What is the product?

Tanzania [10]

Answer:

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

Step-by-step explanation:

$\begin{pmatrix}-3&4\\2&-5\end{pmatrix}\begin{pmatrix}3&-2\\ 1&0\end{pmatrix}$

Multiply the row of the first matrix to the column of the second matrix

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=\left(-3\right)\cdot \:3+4\cdot \:1$

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=\left(-3\right)\left(-2\right)+4\cdot \:0$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=2\cdot \:3+\left(-5\right)\cdot \:1\$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=2\left(-2\right)+\left(-5\right)\cdot \:0\$

$=\begin{pmatrix}\left(-3\right)\cdot \:3+4\cdot \:1&\left(-3\right)\left(-2\right)+4\cdot \:0\\ 2\cdot \:3+\left(-5\right)\cdot \:1&2\left(-2\right)+\left(-5\right)\cdot \:0\end{pmatrix}$

simplifying them we get

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

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Whitepunk [10]

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2 years ago

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C(2, 5), D(3, 1)<br><br> Find the slope of the line that passes through each pair of points.

Tpy6a [65]

Slope=-4 or -4/1

Work:

(2, 5) (3, 1)
x1 y1. x2 y2

M= y2-y1/x2-x1
M= 1-5/3-2
M= -4/1
M=-4

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