Answer:
Step-by-step explanation:
let : x the length and y the width .... ( x > y and x ; y reals numbers )
the perimeter is : 2(x+y)
2(x+y) = 55...(1)
x/y = 7/4 ...(2)
by (2) : x = (7/4)y
subsct in (1) : 2( (7/4)y +y ) =55
(7/2)y +2y =55
multiply by 2
7y +4y = 110
11y = 110
y = 10
x = (7/4)(10)
x = 35/2
Answer:
32 degrees
Step-by-step explanation: So they tell you BE is congruent to BC so triangle BCE is isosceles. We know that angle C is 35 degrees and the triangle is isosceles so angle E is 35 degrees too. Now we do 180-(35+35) and that equals 110 so angle B is 110. And we know that angle EBC and FBA are supplementary angles so 180-110 is 70 degrees so angle FBA is 70 degrees and you can do the same thing with angle DFB and AFB so 180-102 degrees is 78 degrees and to find angle a you just do 180-(70+78) and that equals 32 degrees so angle A is 32 degrees. :)
Answer:
1. < 2. < 3. > 4. = 5. >
Step-by-step explanation:
Answer:
4 ![\frac{3}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B6%7D)
Step-by-step explanation:
The correct answer would most likely be 0.75n - 0.18n