Answer:
x=-6 y=-26
Step-by-step explanation:
in the first is -4 every time, in the second is -20 every time
Step-by-step explanation:
are you sure you wrote the problem here correctly ?
because the distance will be 40km after less than half an hour just by the first car driving. way before the second car even starts.
to be precise, it would be after 60 minutes × 40 / 90
(= how many minutes of an hour are needed to reach 40km while going 90km/h) :
60 × 40 / 90 = 60 × 4 / 9 = 20 × 4 / 3 = 80/3 = 26.67 minutes.
but maybe the question was about 400km distance between the two cars.
so, the first car goes 90km/h for 2 hours.
at that moment it will be 2×90=180km ahead.
that would mean that 220km are still missing for the 400km assumption.
with each hour driving the first car makes 20km more than the second car.
to build up 220km that way would require
220/20 = 11 hours.
plus the 2 original head start hours this would make 13 hours as overall answer.
Answer:
That would be 88!
Step-by-step explanation:
In this type of problem, we would want to use a system of linear equations.
First, we need to find our equations. We know that the two boys traveled 275 km in total, and since x and y count the distance traveled (just in different modes of travel), we can write: x + y = 275.
Next, the problem says that they biked 55 km more than they bussed. So, x = y + 55.
Now that we have two equations to solve for two variables, we can lay them out next to each other:
x + y = 275
x = y + 55
We see that we can substitute x in the first equation with y + 55. This gives us
(y + 55) + y = 275
We solve for y and get y = 110 km by bus. But, we want to know how far they traveled by bike. So, since x = y + 55 and y = 110, we can solve for x by doing 110 + 55 = 165 km by bike.
The answer is 165 kilometers.
