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3 years ago

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A small fruit basket contains the fruit shown. A large basket has the same ratio of fruits as the small basket. If the large bas

ket has 42 total pieces of fruit, how many are pears?
ANSWER ASAP PLEASE.

1 answer:

yarga [219]3 years ago

5 0

Answer: i don’t know

Step-by-step explanation: my brain hurts from trying to figure this out sorry

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Write all the factors of 24:

DerKrebs [107]

The factors are just numbers that can be multiplied to receive the number that is given.

The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24.

1 × 24 = 24
2 × 12 = 24
3 × 8 = 24
4 × 6 = 24

7 0

3 years ago

Read 2 more answers

Find each key feature of the function shown in the graph. Write the range and domain in interval notation, and assume all values

gayaneshka [121]

The domain of the graph is $-8$ while the range of the graph is $-4\leq x$ .

The domain of the graph is input values of "x" for which the function exists while the range is the output values "y" for which the function exists.

For the graph, the domain will be the values of the graph along the x-axis.

Domain = $-8$ (Note that -8 is not included)

For the range, the interval is given as: $-4\leq x$ . Note that the value of 4 is not included since it is opened.

Learn more on domain and range here: brainly.com/question/1942755

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2 years ago

Problem 4: Let F = (2z + 2)k be the flow field. Answer the following to verify the divergence theorem: a) Use definition to find

Viktor [21]

Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk $x^2+y^2\le3$ , I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere $x^2+y^2+z^2=3$ .

a. Let $C$ denote the hemispherical <u>c</u>ap $z=\sqrt{3-x^2-y^2}$ , parameterized by

$\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take the normal vector to $C$ to be

$\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k$

Then the upward flux of $\vec F=(2z+2)\,\vec k$ through $C$ is

$\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du$

$\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du$

$=\boxed{2(3+2\sqrt3)\pi}$

b. Let $D$ be the disk that closes off the hemisphere $C$ , parameterized by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

with $0\le u\le\sqrt3$ and $0\le v\le2\pi$ . Take the normal to $D$ to be

$\vec s_v\times\vec s_u=-u\,\vec k$

Then the downward flux of $\vec F$ through $D$ is

$\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv$

$=\boxed{-6\pi}$

c. The net flux is then $\boxed{4\sqrt3\pi}$ .

d. By the divergence theorem, the flux of $\vec F$ across the closed hemisphere $H$ with boundary $C\cup D$ is equal to the integral of $\mathrm{div}\vec F$ over its interior:

$\displaystyle\iint_{C\cup D}\vec F\cdot\mathrm d\vec S=\iiint_H\mathrm{div}\vec F\,\mathrm dV$

We have

$\mathrm{div}\vec F=\dfrac{\partial(2z+2)}{\partial z}=2$

so the volume integral is

$2\displaystyle\iiint_H\mathrm dV$

which is 2 times the volume of the hemisphere $H$ , so that the net flux is $\boxed{4\sqrt3\pi}$ . Just to confirm, we could compute the integral in spherical coordinates:

$\displaystyle2\int_0^{\pi/2}\int_0^{2\pi}\int_0^{\sqrt3}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=4\sqrt3\pi$

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3 years ago

What is the difference in place value between 2 in 324 and the 2 in 0.324

icang [17]

Answer: the decimal should still be there but you don’t want to have a zero so 3.42 would be correcr

Step-by-step explanation:

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3 years ago

Which number is irrational <br> 25/9

pantera1 [17]

We have a fraction of two integers, so 25/9 is rational. A rational number is any fraction of two integers (as long as the denominator is not zero).

5 0

3 years ago