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Advocard [28]
3 years ago
10

A polygon is a regular _______?

Mathematics
2 answers:
ElenaW [278]3 years ago
6 0

Answer: A polygon is regular if it is an equilateral

ser-zykov [4K]3 years ago
5 0

Answer:

A polygon is regular when all angles are equal and all sides are equal (otherwise it is "irregular").

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Tomtit [17]

Answer:

The option on the top right.

Step-by-step explanation:

Because this is to be done asap, I will not take time to explain.

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The length of a rectangle is five times its width.
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Answer:

length =30m width=6m

hope it helps

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2,23,27,29,30,32,32,34,35,96 select the two outliers
viva [34]
96 and 2 cause they are WAY off. 
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3 years ago
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Find the nth taylor polynomial for the function, centered at c. f(x) = ln(x), n = 4, c = 5
masha68 [24]

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Given:

f(x) = ln(x)

n = 4

c = 3

nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

Now

f(5) = ln 5

f'(x) = 1/x ⇒ f'(5) = 1/5

f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25

f'''(x) = 2/x³  ⇒ f'''(5) = 2/5³ = 2/125

f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Hence,

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Find out more information about nth taylor polynomial here

brainly.com/question/28196765

#SPJ4

3 0
2 years ago
Nick found the quotient of 8.64 and 1.25 × 105. His work is shown below. 1. (8.64 × 101) (1.25 × 105) 2. (8.64 1.25 ) (101 105 )
Savatey [412]

Answer:

B.) No, the power multiplied to 8.64 should have an exponent of 0.

Step-by-step explanation:

took the test on Edgenuity and got it right! Hope this helps and please mark brainliest if can.

4 0
3 years ago
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