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Vika [28.1K]
3 years ago
15

Scott received $88.50 from a customer whose meal bill was $75. What percent tip did Scott receive? A. 12% B. 15% C. 18% D. 20%

Mathematics
1 answer:
Neporo4naja [7]3 years ago
4 0
1st find out how much the tip was:
88.50 - 75.00 = 13.50

Now find the percentage 13.5 is of 75
13.5/75 x 100 = 18% (C)
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When f(x)=4, what is th<br>0​
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Step-by-step explanation:

Not really sure what your question meant but If you trying to find a problem with f(x)=4, then you plug in 4 into the variable of x.

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{(−1, 5), (2, 8), (5, 3), (13, −4)} what are the range
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(x;\ y)\\\\(-1, \fbox5), (2, \fbox8), (5, \fbox3), (13, \fbox{-4})\\\\\boxed{The\ range:y\in\{-4;\ 3;\ 5;\ 8\}}
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3 years ago
Examine triangle ABC.<br><br> What is the value of x?<br><br> 37<br> 48<br> 127<br> 138
Flura [38]

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Set up the equation with what we know:

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4 0
2 years ago
Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9
mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that \mu = 20.5, \sigma = 0.9

What percentage of full-term babies are between 19 and 21 inches long at birth?

The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then

X = 21

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.5}{0.9}

Z = 0.56

Z = 0.56 has a p-value of 0.7123

X = 19

Z = \frac{X - \mu}{\sigma}

Z = \frac{19 - 20.5}{0.9}

Z = -1.67

Z = -1.67 has a p-value of 0.0475

0.7123 - 0.0475 = 0.6648

0.6648*100% = 66.48%

66.48% of full-term babies are between 19 and 21 inches long at birth

5 0
2 years ago
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