Please help me on this problem

Crazy boy [7]

$\textit{internal division of a line segment using ratios} \\\\\\ A(8,6)\qquad B(-2,-9)\qquad \qquad \stackrel{\textit{ratio from A to B}}{3:2} \\\\\\ \cfrac{A\underline{P}}{\underline{P} B} = \cfrac{3}{2}\implies \cfrac{A}{B} = \cfrac{3}{2}\implies 2A=3B\implies 2(8,6)=3(-2,-9)$

$(\stackrel{x}{16}~~,~~ \stackrel{y}{12})=(\stackrel{x}{-6}~~,~~ \stackrel{y}{-27})\implies P=\underset{\textit{sum of the ratios}}{\left( \cfrac{\stackrel{\textit{sum of x's}}{16-6}}{3+2}~~,~~\cfrac{\stackrel{\textit{sum of y's}}{12-27}}{3+2} \right)} \\\\\\ P=\left( \cfrac{10}{5}~~,~~\cfrac{-15}{5} \right)\implies P=(2~~,~~-3)$

5 0

2 years ago

Evaluate the following if k=0.5, n=-3, and p=-2: K+n(p^2)

ivann1987 [24]

Answer:

-11.5

Step-by-step explanation:

$K + n( {p}^{2} ) \\ \\ plug \: K = 0.5, \: n = - 3, \: p = - 2 \\ \\ K + n( {p}^{2} ) \\ \\ = 0.5 + ( - 3) \{ {( - 2)}^{2} \} \\ \\ = 0.5 - 3 \{ 4 \} \\ \\ = 0.5 - 12 \\ \\ = - 11.5$

5 0

3 years ago

Find the probability that the senator was in the Democratic party, given that the senator was returning to office.

shutvik [7]

Answer:

The probability that the senator was in the Democratic party, given that the senator was returning to office is 0.4715.

Step-by-step explanation:

The complete question is:

Sophia made the following two-way table categorizing the US senators in 2015 by their political party and whether or not it was their first term in the senate.

Democratic Republican Independent Total

First Term 11 28 11 50

Returning 33 26 11 70

Total 44 54 22 120

Find the probability that the senator was in the Democratic party, given that the senator was returning to office.

Solution:

The conditional probability of an event A given that another event X has already occurred is given by:

$P(A|X)=\frac{P(A\cap X)}{P(X)}$