Answer:
The radical notation is ![3x\sqrt[3]{y^2z}](https://tex.z-dn.net/?f=3x%5Csqrt%5B3%5D%7By%5E2z%7D)
Step-by-step explanation:
Given
![\sqrt[3]{27 x^{3} y^{2} z}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%20x%5E%7B3%7D%20y%5E%7B2%7D%20z%7D)
Step 1 of 1
Write the expression using rational exponents.
![\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D%3D%5Cleft%28a%5E%7Bm%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)





Simplify 
![$=3 x \sqrt[3]{y^{2} z}$](https://tex.z-dn.net/?f=%24%3D3%20x%20%5Csqrt%5B3%5D%7By%5E%7B2%7D%20z%7D%24)
Learn more about radical notation, refer :
brainly.com/question/15678734
The answer is -4. I solved it on a calculator and got -4
Answer :y=4 x=2
Step-by-step explanation:
Check the one-sided limits:


If <em>f(x)</em> is to be continuous at <em>x</em> = 5, then these two limits should have the same value, which means
5<em>k</em> = 200
<em>k</em> = 200/5
<em>k</em> = 40
Before we do this problem, let's go over a little algebra terminology.
The number in front of your variable is called your <em>coefficient </em>and notice that the <em>x</em> at the end of the problem does not have a coefficient.
When that happens, when there is no number in front of your variable, you can put a 1 there to fill that position. So -x can be thought of as -1x.
Next let's change all our minus signs to plus negatives.
So the problem reads 3x + 5 + 7x + -3 + -1x + 2.
Now let's simplify this by combining like terms.
We can combine our "x" terms first.
3x + 7x + -1x simplifies to +9x.
Now, 5 + -3 + 2 simplifies to 4.
So our answer is 9x + 4.