No I have not had that do that to me before It has always loaded my ads and sent me right back to the answer
Answer:
<u>Call by reference</u>
In an function if the variables are passed as reference variables this means that the variables are pointing to the original arguments.So the changes made in the function on the reference variables will be reflected back on the original arguments.
For example:-
#include<stdio.h>
void swap(&int f,&int s)
{
int t=f;
f=s;
s =temp;
}
int main()
{
int n,m;
n=45;
m=85;
swap(n,m);
printf("%d %d",m,n);
return 0;
}
the values of m and n will get swapped.
<u>
Call by value</u>
In this program the values of m and n will not get swapped because they are passed by value.So duplicate copies of m and n will be created and manipulation will be done on them.
#include<stdio.h>
void swapv(int f,int s)
{
int t=f;
f=s;
s=temp;
}
int main()
{
int n,m;
n=45;
m=85;
swapv(n,m);
printf("%d %d",n,m);
return 0;
}
by typing ctrl+ s on keyboard
The answer is True bc it saves you time and is efficient
Answer:
Relative Advantage.
Explanation:
Modern computer owners will be reminded of such a slow, user-unfriendly DOS program. Whenever Apple released System 1 as well as Microsoft launched Windows, all among these became far harder to just use, such revolutionary technologies circulated easily owing towards its relative advantage.
So, the following are the reason which describe that answer is correct according to the question.
