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3 years ago

What are the zeros of the function y=x(x-2)(x+6)²

Mathematics

2 answers:

sweet [91]3 years ago

6 0

i think the answer is c

evablogger [386]3 years ago

3 0

Answer:

A. -6, 0, and 2

Step-by-step explanation: PLATO

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If (x -y)^2= 200 and x^2 + y^2= 50 what Is the value of xy?

Dvinal [7]

$(x-y)^{2}= x^{2} -2xy+ y^{2} \\ xy= \frac{x^{2} +y^{2}-(x-y)^{2}}{2} = \frac{50-200}{2} = \frac{-150}{2} =-75$

3 0

3 years ago

Find 5 consecutive whole numbers if it is known that the sum of the squares of the first 3 numbers is equal to the sum of the sq

zlopas [31]

Let numbers be x-1,x,x+1,x+2,x+3

(x-1)^2 + x^2 + (x+1)^2 = (x+2)^2 + (x+3)^2

$( x^{2} -2*x+1)+ x^{2} +( x^{2} +2*x+1)= ( x^{2} +4x+4)+( x^{2} +6x+9)
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$3 x^{2} +2=2 x^{2} +10x+13⇒
 x^{2} =10x+11⇒
 x^{2} -10x-11=0
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x=11 or -1(not a whole number)
x=11
the numbers are 10,11,12,13,14

3 0

4 years ago

Use the image for part a, b, and c. Show work.

d1i1m1o1n [39]

Answer:

A. no

B. see below

C. KL = 14

Step-by-step explanation:

A. AA similarity requires two angles in one triangle be congruent with two angles in the other. Here, only one angle is marked in each triangle, so AA similarity cannot apply.

B. See the explanation given in Part A.

C. The triangles are similar because corresponding sides are proportional (and the angle between them is congruent). The sides that correspond are the ones on either side of the marked angle. The sides in the larger triangle JKL are double the measure of the sides in the smaller triangle GHI. Hence, for HI = 7, KL = 2·7 = 14.

5 0

4 years ago

NEED ANSWERS ASAP!!

Oliga [24]

Answer:

for 13.) angles 4, 5 and 8 equal 135 and 3, 6 and 7 equal 45

for 14.) 1 equals 120 and 2 equals 60

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3 years ago

( 9³. 9 . 9⁰ ÷ 9⁴. 9¹ )-³ simplify and calculate this algebraic expression

deff fn [24]

Answer:

1/729

Step-by-step explanation:

According to the Order of Operations, the expression will be evaluated like this.

$\left(9^3\cdot9\cdot\dfrac{9^0}{9^4}\cdot9^1\right)^{-3}\\\\=\left(729\cdot9\cdot\dfrac{1}{6561}\cdot9\right)^{-3}\\\\=\left(\dfrac{6561}{6561}\cdot9\right)^{-3}=9^{-3}=\boxed{\dfrac{1}{729}}$

If you were to combine exponents before doing the evaluation, you would have ...

(9^3·9^1·9^0·9^-4·9^1)^-3 = 9^((3+1+0-4+1)·(-3)) = 9^-3 = 1/729

Note that the 9^1 term in the original expression is not in the denominator. The preceding division is done before the result is multiplied by 9^1, according to the order of operations.

Some authors use the ÷ symbol to mean "everything on the left divided by everything on the right". Some students fail to put needed parentheses around denominators. As a consequence we're not sure precisely what it is we're supposed to evaluate without seeing the original typeset expression.

8 0

2 years ago