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Marta_Voda [28]
3 years ago
10

when added to the number that is produced by doubling the number x the result is equal to 8 times the number that is 5 less than

x what is the value of x?
Mathematics
2 answers:
Olenka [21]3 years ago
6 0
X is 4
4+4=8
4is less than 5
Serhud [2]3 years ago
5 0
2x + x = 8(x-5)
3x = 8x-40
-5x = 40
x = -8

Just tell me if you need more assistance figuring out how I concluded that.
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Write a mixed number that is equivalent to 16/3.
mars1129 [50]
A mixed number is an integer--whole number--in front of a fraction. To calculate this, you have to divide the numerator by the denominator and put the remainder over the denominator. 

Since 3 goes into 16 wholly 5 <em />times with 1 left over, 16/3 = 5 1/3.

Hope this helps!
3 0
3 years ago
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A basketball-player scores a free-throw with probability 0.9. What is the probability that her first miss occurs on the 6th shot
-BARSIC- [3]

Answer:

Pr = 0.059049

Step-by-step explanation:

Given

p = 0.9 --- probability of scoring

Required

Probability that his first miss is his 6th shot

Let q represent the event that he did not score.

Using complement rule:

q = 1 - p = 1 - 0.9 = 0.1

The event that his first miss is his 6th is represented as:

p p p p p q ---- That he scoress the first 5 attempts

So, the probability is:

Pr = p^5 * q

Pr = 0.9^5 * 0.1

Pr = 0.059049

7 0
3 years ago
If you are using Cosine and need to solve for an unknown hypotenuse, you should...
kifflom [539]

Using cosine, we can find the hypotenuse by using the formula below;

hypotenuse = adjacent / cos ∅

<h3 /><h3 /><h3>Trigonometric ratios:</h3>
  • Trigonometric ratios are ratios of sides of a right angled triangle.
  • The simplest ratios are cosine, sine and tangent.

Using cosine, the hypotenuse side can be solved as follows:

cosine ∅ = adjacent / hypotenuse

cross multiply

hypotenuse cos ∅ = adjacent

divide both sides by cos ∅

hypotenuse cos ∅ / cos ∅ = adjacent / cos ∅

Therefore,

hypotenuse = adjacent / cos ∅

learn more on cosines here: brainly.com/question/10657732?referrer=searchResults

6 0
2 years ago
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
Find the midpoint M of the line segment joining the points C = (-1, 1) and D = (5, – 7).<br> =<br> =
lukranit [14]

Answer: (2,-3)

Step-by-step explanation:

5 0
2 years ago
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