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2 years ago

What is the length of the hypotenuse? 55 ft and 48 ft

Mathematics

1 answer:

34kurt2 years ago

6 0

Answer:

$\sqrt{55^2+ 48^2} = 73$

Step-by-step explanation:

$c=\sqrt{a^2 + b^2}$

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If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

In ΔVWX, m ∠ V = ( 5 x + 7 ) ∘ m∠V=(5x+7) ∘ , m ∠ W = ( 4 x + 16 ) ∘ m∠W=(4x+16) ∘ , and m ∠ X = ( 5 x + 17 ) ∘ m∠X=(5x+17) ∘ .

Otrada [13]

Answer:

idkyuhhggrtwuoiwe

Step-by-step explanation:

IFNDKS

6 0

3 years ago

4th grade conversions please help!!

MAVERICK [17]

6 inches of yarn make 1 bracelet.

5 feet of yarn make how many bracelets?

1 foot = 12 inches
5 feet = 12 * 5 inches = 60 inches

6 inches of yarn make 1 bracelet
60 inches of yarn make x bracelets

6/1 = 60/x

Cross multiply

6x = 60

x = 10

60 inches yarn make 10 bracelets.

6 0

4 years ago

Read 2 more answers

Mr.Mole left his burrow and started digging his way down at a constant rate

Svetlanka [38]

Answer:

Mr. Mole is descending by 2.4 meters per minute

Step-by-step explanation:

Let

x ----> the time in minutes

y ---> the distance in meters

we know that