All categories

3 years ago

A cyclinder has a volume of 703 π cm^3 and a height of 18.5 cm. What can be concluded about the cyclinder? Check all that apply.

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

7 0

Answer:

See below.

Step-by-step explanation:

A) applies here because Volume= π r^2 h where π r^2 is the area of the base.

D) The area of the base = 703 π / 18.5 = 38π cm^2.

E) Check that the volume is 703π cm^3:

V = π * 38* 18.5 = 703π.

denis-greek [22]3 years ago

6 0

Answer:

See step-by-step explanation.

Step-by-step explanation:

Statements that apply:

A) The volume formula can be used to find the area of the base. (V=A*h)

D) The area of the base is 38π

$A=\frac{V}{h} \\\\A=\frac{703\pi }{18.5}=38\pi$

E) $A=\frac{V}{h} \\\\A=\frac{703\pi }{18.5}=38\pi$

Statements that don't apply and why:

B) The volume should be divided by the height to find the area

C) The radius of the cylinder is 38/2=18, which is not the half of 18.5

You might be interested in

The chapter is 8pages long. kosta read 1/4 of the chapter aloud.then christina read three pages to the class. How many pages hav

pshichka [43]

Number of pages that the chapter has = 8
Number of pages of the chapter that Kosta read = (1/4) * 8
   = 1 * 2
   = 2
The number of pages of the chapter read by Christina = 3
Then
The total number of pages of the
chapter read by both of them = 2 + 3
      = 5
So the total number of pages of the chapter that has been read by Kosta and Christina is 5. I hope the procedure is clear enough for you to understand.

8 0

3 years ago

A new drug claims to reduce the number of migraines an individual suffers. In a study on the effectiveness of the new drug, 50 s

lana66690 [7]

Answer:

I got A on edg

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) Now, here sample of NBA players is 26 so n = 26.

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

4 years ago

Rachel can buy licorice sticks for $0.75 and cherry candies for $0.50 and has a budget of $25 if her expenses are represented by

likoan [24]

You can buy 50 of the cherry candies with all of the 25$ because you do 25 divided by 0.50 and get 50 and then if you would like to check that do 50 x 0.50 and you will still get 25$

6 0

3 years ago

Subtract 3/y-2 - 1/y+3

Helen [10]

To subtract fractions, we need a common denominator.

$\frac{3}{y-2}$ - $\frac{1}{y+3}$

the common denominator will be (y-2)(y+3)

$\frac{3(y+3)-1(y-2)}{(y-2)(y+3)}$
$\frac{3y + 9 - y + 2}{(y-2)(y+3)}$
$\frac{2y + 11}{(y-2)(y+3)}$

The answer above will be the simplified form.

3 0

4 years ago