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3 years ago

Subtract 3/y-2 - 1/y+3

1 answer:

3 0

To subtract fractions, we need a common denominator.

$\frac{3}{y-2}$ - $\frac{1}{y+3}$

the common denominator will be (y-2)(y+3)

$\frac{3(y+3)-1(y-2)}{(y-2)(y+3)}$
$\frac{3y + 9 - y + 2}{(y-2)(y+3)}$
$\frac{2y + 11}{(y-2)(y+3)}$

The answer above will be the simplified form.

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What does pi equal exactly

Scilla [17]

3.141562.... And it goes on and on and on

6 0

3 years ago

Read 2 more answers

A certain ore is 31.8% nickel by mass. How many kilograms of this ore would you need to dig up to have 25.0 g of nickel?

natulia [17]

It will need 1.8 kilograms to have 25.0 g of nickel

6 0

3 years ago

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

<u>x = 2</u>
<u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

4 0

2 years ago

(x-1)(x-3)(x+5)(x+7)=297

mihalych1998 [28]

First simplify the expression into polynomial form,

$(x-1)(x-3)(x+5)(x+7)=297$

$x^4+8x^3-10x^2-104x+105=297$

$x^4+8x^3-10x^2-104x-192=0$

Now factor into,

$(x-4)(x+8)(x^2+4x+6)=0$

Which means the solutions are,

$x-4=0\implies\boxed{x_1=4}$

$x+8=0\implies\boxed{x_2=-8}$

and then two complex solutions because determinant of the third factor $D\lt0$ ,

$x^2+4x+6=0$

$x^2+4x+4=-2$

$(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}$

Hope this helps :)

5 0

3 years ago

Read 2 more answers

The information below applies to a competitive firm that sells its output for $40 per unit.

drek231 [11]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

On producing 150 units, its average total cost = $24.50

We need to find the total cost.

As we know that

$Average\ cost=\dfrac{Total\ cost}{No.\ of\ units}\\\\total\ cost=Average\ cost\times No.\ of\ units\\\\total\ cost=24.50\times 150\\\\total\ cost=\$3675$

Hence, total cost is $3675.00.

Therefore, Option 'c' is correct.

3 0

3 years ago