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Nitella [24]
3 years ago
9

Subtract 3/y-2 - 1/y+3

Mathematics
1 answer:
Helen [10]3 years ago
3 0
To subtract fractions, we need a common denominator.

\frac{3}{y-2} - \frac{1}{y+3}

the common denominator will be (y-2)(y+3)

\frac{3(y+3)-1(y-2)}{(y-2)(y+3)}
\frac{3y + 9 - y + 2}{(y-2)(y+3)}
\frac{2y + 11}{(y-2)(y+3)}

The answer above will be the simplified form.
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Step-by-step explanation:

If △XPS ≅△DNF, their corresponding sides would be congruent. This implies that:

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