Question

What is the sum of the first 12 terms of the geometric series below 1/2+2+8+32+

Answer 1

∴$\frac{1}{2} +2+8+32.......12^{th}term$ =2796202.5

Step-by-step explanation:

First term(a) = $\frac{1}{2}$   common ratio(r)     =$\frac{2}{\frac{1}{2} }$   =4

n= 12

$S_{n}=\frac{a(r^n-1)}{(r-1)}$

$S_{12}=\frac{\frac{1}{2}(4^{12}-1) }{4-1}$ =2796202.5

∴$\frac{1}{2} +2+8+32.......12^{th}term$ =2796202.5