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igor_vitrenko [27]
3 years ago
6

13.) –3(y+3)=2y+3 What is the answer to this

Mathematics
2 answers:
WINSTONCH [101]3 years ago
8 0
-12/5, you would distribute them combine like terms
Morgarella [4.7K]3 years ago
6 0
Answer is -12/5 or -2.4
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A certain cylindrical tank holds 20,000 gallons of water which can be drained from the bottom of the tank in 20 minutes the volu
zalisa [80]
Given that the volume of water remaining in the tank after t minutes is given by the function

V(t)=20,000\left(1- \frac{t}{20} \right)^2

where V is in gallons, 0 ≤ t ≤ 20 is in minutes, and t = 0 represents the instant the tank starts draining.

The rate at which water is draining four and a half minutes after it begins is given by

\left.
 \frac{dV}{dt} \right|_{t=4 \frac{1}{2} = \frac{9}{2} 
}=\left[40,000\left(1- \frac{t}{20} \right)\left(- \frac{1}{20} 
\right)\right]_{t= \frac{9}{2} } \\  \\ =\left[-2,000\left(1- 
\frac{t}{20} \right)\right]_{t= \frac{9}{2} }=-2,000\left(1- 
\frac{4.5}{20} \right) \\  \\ =-2,000(1-0.225)=-2,000(0.775)=-1,550\, 
gallons\ per\ minute

Therefore, the water is draining at a rate of 1,550 gallons per minute four ans a half minutes after it begins.

Answer option E is the correct answer.
4 0
3 years ago
I need help with this problem:(​
steposvetlana [31]

Answer:

8

Step-by-step explanation:

According to Euclidean theorem

m^2 = 4×16

m^2 = 64

m = 8

3 0
3 years ago
Keshawn is constructing the inscribed circle for △PQR. He has already used his compass and straightedge to complete the part of
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Construct the perpendicular to <span><span>QR</span><span>¯¯¯¯¯</span></span><span> that passes through point </span>X<span>.</span>
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3 years ago
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3 years ago
What is an equation of the line that passes through the points (4, -6)<br>and (8, -4)
QveST [7]

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-6)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{4}}}\implies \cfrac{-4+6}{4}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{4}) \\\\\\ y+6=\cfrac{1}{2}x-2\implies y=\cfrac{1}{2}x-8

3 0
3 years ago
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