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bekas [8.4K]
3 years ago
13

Absolute Value Inequalities -7|x-6|>-56

Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0

Answer: \begin{bmatrix}\mathrm{Solution:}\:&\:\mathrm{True\:for\:all}\:x\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}

Step-by-step explanation:

7\left|x-6\right|>-56

\frac{7\left|x-6\right|}{7}>\frac{-56}{7}

\left|x-6\right|>-8

\mathrm{True\:for\:all}\:x

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If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?
Irina18 [472]

Answer:

36

Step-by-step explanation:

Hello,

If X=x^2 it becomes

X^3-289X^2-X+289=(X^2-1)(X-289)

and 289=17^2

X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)

So,

x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

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3 years ago
What’s the answer to this problem?
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7 0
4 years ago
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Answer:

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Step-by-step explanation:

For this case we must build a quotient that, when multiplied by the divisor, eliminates the terms of the divide until it reaches the remainder.

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Step-by-step explanation:

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